预期类型变量是使用 Apollo 的对象

Expected type variable to be an object using Apollo

我在 GraphQL Playground 中有一个工作查询,我正在尝试使用 Apollo 开始工作。我似乎无法将变量正确传递给查询。

这是我的代码:

public render() {
  const CONVERSATION = gql`
    query GetConversation(
      $conversationId: ConversationWhereUniqueInput!
    ) {
      conversation(where: $conversationId) {
        id
        title            
      }
    }
  `
  const conversationId: any = this.props.conversation
  console.log(conversationId) // works.

  return (
    <ApolloProvider client={this.client}>
      <div>
        <Query query={CONVERSATION} variables={{ conversationId }}>
          {({ loading, error, data }) => {
            if (error) {
              return <div>${JSON.stringify(error)}</div>
            }
            if (loading) {
              return <div>Loading...</div>
            }
            return <div>{JSON.stringify(data)}</div>
          }}
        </Query>
      </div>          
    </ApolloProvider>
  )
}

我收到的错误信息是:

${"graphQLErrors":[],"networkError":{"name":"ServerError","response":{},"statusCode":400,"result":{"errors":[{"message":"Variable \"$conversationId\" got invalid value \"cjrtfagwc00bq0a300njz594r\"; Expected type ConversationWhereUniqueInput to be an object.","locations":[{"line":1,"column":23}]}]}},"message":"Network error: Response not successful: Received status code 400"}

[GraphQL error]: Message: Variable "$conversationId" got invalid value "cjrtfagwc00bq0a300njz594r"; Expected type ConversationWhereUniqueInput to be an object., Location: [object Object], Path: undefined

我认为通过将我的变量作为 variables={{ conversationId }} 传递,我实际上是在按要求传递一个对象。我做错了什么?

编辑 Benjie帮我找出问题所在

我只需要将 const conversationId: any = this.props.conversation 更改为 const conversationId: any = { this.props.conversation }

您正在传递变量:

{
  "conversationId": "cjrtfagwc00bq0a300njz594r"
}

这很好。问题是你的查询被定义为 conversationId 变量(你已经给了字符串(或 ID?)值 "cjrtfagwc00bq0a300njz594r")应该是 ConversationWhereUniqueInput(哪个是一个输入对象):

$conversationId: ConversationWhereUniqueInput!

这两种类型(IDConversationWhereUniqueInput)不兼容。

鉴于您的变量命名,我怀疑您想更改 GraphQL 查询,以便它通过 conversationId 属性 作为 where 参数的一部分:

query GetConversation(
  $conversationId: ID!
) {
  conversation(where: {conversationId: $conversationId}) {
    id
    title            
  }
}