Swift PrepareForSegue 错误线程 1：EXC_BREAKPOINT（代码=EXC_ARM_BREAKPOINT，子代码=0xdefe

Question

我在尝试编译 PrepareForSegue 函数时遇到了很大的问题：

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject!) {
    if segue.identifier == "findMap" {
        let MapViewController = segue.destinationViewController as UIViewController
        if sender as UITableView == self.searchDisplayController!.searchResultsTableView {
            let indexPath = self.searchDisplayController!.searchResultsTableView.indexPathForSelectedRow()!
            let destinationTitle = filteredDepartments[indexPath.row].name
            MapViewController.title = destinationTitle
        } else {
            let indexPath = self.tableView.indexPathForSelectedRow()!
            let destinationTitle = departments[indexPath.row].name
            MapViewController.title = destinationTitle
        }
    }
}

错误在 "trap" 行的线程部分打开：

--> 0x2f6e18: 陷阱

错误码如上：

--> 线程 1: EXC_BREAKPOINT(code=EXC_ARM_BREAKPOINT, subcode=0xdefe

我认为错误在这一行：

if sender as UITableView == self.searchDisplayController!.searchResultsTableView {

但是我不知道怎么解决，所以请帮助我...

Answer 1

很难说出您的代码的含义，但我猜您的意思是：

if sender === self.searchDisplayController!.searchResultsTableView {

请注意使用三等号运算符表示 "is the same object as"。

Swift PrepareForSegue 错误线程 1：EXC_BREAKPOINT（代码=EXC_ARM_BREAKPOINT，子代码=0xdefe

Swift PrepareForSegue ERROR Thread 1: EXC_BREAKPOINT(code=EXC_ARM_BREAKPOINT, subcode=0xdefe

multithreading

swift