如何将单个参数传递给单独的特征文件

Question

我在下面尝试将参数发送到单独的功能文件（通过遵循 this example ）但是，它没有按预期工作。

project.feature

   * def id = '55000000005021'
   * def result = call read('delete_project.feature')

删除_project.feature

 Given path 'project', '#(id)'
 When method DELETE
 Then status 200
 Then match response.status == 'success'

低于异常

com.intuit.karate.exception.KarateException: projects.feature:48 - delete_project.feature:11 - status code was: 404, expected: 200, response time: 239, url: https://localhost:8080/project/%23(id) response: {"status":"failure","data":{"error_code":"INVALID_URL_PATTERN","message":"Please check if the URL trying to access is a correct one"}} at ✽.* def result = call read('delete_project.feature') (projects.feature:48)

还有一个疑问，如何通过传递 id 列表来迭代它。我在 foo 变量中有多个 id，我想为该 foo 变量中的每个可用 id 调用 delete_project.feature。

* def foo = get response.data[*].id

Answer 1

我认为您将路径参数过于复杂，更改为：

Given path 'project', id

并阅读文档的这一部分：https://github.com/intuit/karate#rules-for-embedded-expressions

如何将单个参数传递给单独的特征文件

How to pass single param to separate feature file

karate