SQL 按整数值的连续范围分组

Question

我有一个table喜欢：

id  number  owner
47   100      1
48   101      1
49   102      1
50   103      2
51   104      2
52   105      2
53   106      1
54   107      1
55   108      2
56   109      2
57   110      2

如何按数字和所有者的连续范围分组以获得如下结果：

from_number  to_number    owner
   100          102         1
   103          105         2
   106          107         1
   108          110         2

我尝试了：SELECT MIN(number), MAX(number), owner FROM table GROUP BY owner，但得到了结果：

MIN(number)  MAX(number)  owner 
   100          107        1
   103          110        2

Answer 1

这是一种 "groups-and-islands" 问题。您可以通过从 number 中减去一个序列来完成此操作。当 number 是连续的时，差异是恒定的：

select owner, min(number) as from_number, max(number) as to_number
from (select t.*,
             row_number() over (partition by owner order by number) as seqnum
      from t
     ) t
group by owner, (number - seqnum);

Answer 2

您可以尝试生成两个行号并取其差值

select owner, min(number) as min_number, max(number) as max_number
from (select a.*,
             row_number() over (partition by owner order by number) as rn1,
             row_number() over(order by number) rn2
      from table_name a
     ) t
group by owner, (rn2 - rn1);

SQL 按整数值的连续范围分组

SQL Group by continuous range of integer values

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