有没有办法让这段代码更短？ （反应收集器）

Question

const backwardsFilter = (reaction, user) => reaction.emoji.name === '⏪' && user.id === message.author.id;
const forwardsFilter = (reaction, user) => reaction.emoji.name === '⏩' && user.id === message.author.id;
const backwards = msg.createReactionCollector(backwardsFilter, {time: 90000});
const forwards = msg.createReactionCollector(forwardsFilter, {time: 90000});

我试图为两个收集器制作一个过滤器，但仍然必须输入此 (x,y,z) => filter(x,y,z,'⏪')

const filter = (reaction, user, c, emoji) => reaction.emoji.name === emoji && user.id === message.author.id;
const backwards = msg.createReactionCollector((x,y,z) => filter(x,y,z,'⏪'), {time: 90000});
const forwards = msg.createReactionCollector((x,y,z) => filter(x,y,z,'⏩'), {time: 90000});

Answer 1

您可以创建一个高阶函数，一个接受您要查找的字符的函数，returns一个接受三个参数的函数（reaction、user、c，对应你当前的(x, y, x) =>)和returns相应的过滤操作。

此外，这里的任何代码中似乎都没有使用 c（与 z 相同），因此请随意将其从参数列表中删除。

const makeFilter = emoji => (reaction, user) => reaction.emoji.name === emoji && user.id === message.author.id;
const backwards = msg.createReactionCollector(makeFilter('⏪'), {time: 90000});
const forwards = msg.createReactionCollector(makeFilter('⏩'), {time: 90000});