关联类型以通过特征和泛型类型规范化可序列化数据

Associated types to normalize serializable data via traits and a generic type

我试图实现一种类型,该类型将 "enforce" 一些模式用于我在 Tide 中的响应,但不断收到 "Items from traits can only be used..." 编译器错误。

#![feature(async_await, futures_api, await_macro, arbitrary_self_types)]
#![allow(proc_macro_derive_resolution_fallback)]

use serde_derive::Serialize;
use tide::{body::Json, IntoResponse, Response};

#[derive(Serialize)]
struct Document<Attrs, Rels> {
    data: PrimaryData<Attrs, Rels>,
}

#[derive(Serialize)]
struct PrimaryData<Attrs, Rels> {
    id: i32,
    kind: String,
    attributes: Attrs,
    relationships: Rels,
}

trait IntoPrimaryData: Send {
    type Attrs: serde::Serialize;
    type Rels: serde::Serialize;

    fn into_primary_data(self) -> PrimaryData<Self::Attrs, Self::Rels>;
}

struct ServiceResponse<T: IntoPrimaryData>(T);

impl<T: IntoPrimaryData> IntoResponse for ServiceResponse<T> {
    fn into_response(self) -> Response {
        Json(Document {
            data: self.0.into_primary_data(),
        })
        .with_status(http::status::StatusCode::OK)
        .into_response()
    }
}

#[derive(Serialize)]
struct User {
    id: i32,
    primary_email: String,
}

#[derive(Serialize)]
struct UserAttrs {
    primary_email: String,
}

impl IntoPrimaryData for User {
    type Attrs = UserAttrs;
    type Rels = ();

    fn into_primary_data(self) -> PrimaryData<Self::Attrs, Self::Rels> {
        PrimaryData {
            id: self.id,
            kind: "user".into(),
            attributes: UserAttrs {
                primary_email: self.primary_email,
            },
            relationships: (),
        }
    }
}

fn main() {}
[dependencies]
tide = "0.0.5"
http = "0.1.16"
serde = "1.0.89"
serde_derive = "1.0.89"

编译器returns错误

error[E0599]: no method named `with_status` found for type `tide::body::Json<Document<<T as IntoPrimaryData>::Attrs, <T as IntoPrimaryData>::Rels>>` in the current scope
  --> src/main.rs:34:10
   |
34 |         .with_status(http::status::StatusCode::OK)
   |          ^^^^^^^^^^^
   |
   = note: the method `with_status` exists but the following trait bounds were not satisfied:
           `tide::body::Json<Document<<T as IntoPrimaryData>::Attrs, <T as IntoPrimaryData>::Rels>> : tide::response::IntoResponse`
   = help: items from traits can only be used if the trait is implemented and in scope
   = note: the following trait defines an item `with_status`, perhaps you need to implement it:
           candidate #1: `tide::response::IntoResponse`

我不确定为什么会收到此错误,但我觉得这与 data: self.0.into_primary_data() 行不够 "specific" 行有关,并且不知道是什么Self::AttrsSelf::Rels 的类型是。但是,我知道如果其中一个嵌套类型没有实现 serde::Serialize,我也会遇到同样的错误(减去关于 "items from traits can only be..." 的帮助提示),但据我所知,我已经添加了那些在他们需要的任何地方都有界限。

我已经尝试过用一百万种方式来做这件事,但似乎无法想出一种方法来为我的回答获得一些规范化的结构。

我正在使用 rustc 1.34.0-nightly (02c4c2892 2019-02-26)

您没有正确指定关联类型的完整范围。

Json 仅在其包含的类型同时实现 SendSerialize:

时才实现 IntoResponse
impl<T: Send + Serialize> IntoResponse for Json<T>

您需要在关联类型的边界中包含 Send

trait IntoPrimaryData: Send {
    type Attrs: serde::Serialize + Send;
    //                           ^^^^^^
    type Rels: serde::Serialize + Send;
    //                          ^^^^^^

    fn into_primary_data(self) -> PrimaryData<Self::Attrs, Self::Rels>;
}

调试步骤

这行错误消息看起来很有希望:

the method `with_status` exists but the following trait bounds were not satisfied:
`tide::body::Json<Document<<T as IntoPrimaryData>::Attrs, <T as IntoPrimaryData>::Rels>> : tide::response::IntoResponse`

这表明我们可以调用 with_status,除非编译器不知道该类型实现了特征。从那里,我去了 Json 的文档,看看它是否实现了 IntoRespose 如果是,在什么条件下:

impl<T: Send + Serialize> IntoResponse for Json<T>

据此,我们知道这个T必须是PrimaryData<T::Attrs, T::Rels>并且它必须实现Send + Serialize

我们看到 PrimaryData 导出 Serialize:

#[derive(Serialize)]
struct PrimaryData<Attrs, Rels> {

根据现有知识,我知道大多数 derived 特征都要求所有泛型类型也实现该特征。它不太明显,但对于 Send.

也是如此

从那里开始,就是要证明 AttrsRels 的特定类型实现了 SerializeSend。关联的类型边界处理一个但不处理另一个。

决定在哪里放置边界是一个意图和风格的问题——它们可以在函数、impl 块或特征中继续。由于该特征已经提到 Serialize,因此添加额外的界限似乎是一个自然的地方。

我也犯了一个大错误——我假设你已经正确指定了边界并且 运行 变成了 ()。只有当我尝试应用建议的副本时,我才意识到边界不正确。

另请参阅: