Puppeteer

Question

每次我将 xpath 传递给我的函数时，它 returns string is not a valid XPath expression。这是为什么？

const searchSelector = '//*table/tbody/tr/td[1]';

const result = await page.evaluate(element => {
      return element.textContent;
    }, await page.$x(searchSelector));

Answer 1

因为它不是有效的 XPath，请考虑这个 XPath：

//table/tbody/tr/td[1]

或者如果你需要依赖 class name:

//table[@class = 'classname']/tbody/tr/td[1]

Puppeteer - 字符串不是有效的 XPath 表达式

Puppeteer - string is not a valid XPath expression

xpath