Corona SDK 对于矮人要塞之类的游戏是否足够快？

Question

我想做一个矮人要塞之类的游戏。 Corona SDK 会足够快吗？我将如何存储每个单独块的数据。由于我无法在 Lua 中进行枚举，我将如何定义块的类型？

Answer 1

为什么不能在 Lua 中进行枚举？只需使用简单的 table.

brickType = { A = 1,
              B = 2,
              C = 3,
}

myFristBrick = { weight = 500,
                 volume = 50,
                 type = brickType.C
}

您可以使用 Lua table 为非常复杂的数据结构建模。因此，存储砖块数据是您最不应该关心的问题。

Answer 2

我将其与元表一起使用，以模拟枚举类型

local enumType_MT = {
    __newindex = function (t, k, v)
        if t [k] then
            print ('redeclaring enum type ' .. k .. ' not permited')
        else
            rawset (t, k, {})
            local c
            for c = 1, #v do
              rawset (t [k], v[c], c)
              rawset (t[k], c, v[c])
            end
         end
    end
}

local myEnumTypes = {}
setmetatable( myEnumTypes, enumType_MT )

myEnumTypes ['foo']  = {'brick_A', 'brick_B', 'brick_C'}
myEnumTypes ['doo']  = {'brick_E', 'brick_F', 'brick_G'}

myVar = myEnumTypes['foo'].brick_A
print (myVar) -- outputs 1
myVar = myEnumTypes['foo']['brick_C']
print (myVar) -- outputs 3
myVar = myEnumTypes['foo'][2]
print (myVar) -- outputs 'brick_B'

myVar = myEnumTypes['doo'].brick_A
print (myVar) -- outputs nil as brick_A not in doo
myVar = myEnumTypes['doo']['brick_C']
print (myVar) -- outputs nil as brick_C not in doo
myVar = myEnumTypes['doo'][2]
print (myVar) -- outputs 'brick_F'

Corona SDK 对于矮人要塞之类的游戏是否足够快？

Is Corona SDK fast enough for a Dwarf Fortress like game?

lua

enums

coronasdk