我的最小部分没有显示真正的最小值

Question

#include<stdio.h>
int main(){
float a[100],sum=0.0,avg,havg[100],min,max;
int i;
for(i=0; i!=-1;i++){
    printf("Enter number : ");
    scanf("%f",&a[i]);
    max = a[0];
    min = a[0];
    sum+=a[i];
    avg= sum/(i+1);
    havg[i]=avg/2;
    printf("Loop %d Summation : %.0f ",i,sum);
    printf("Half of Avg. : %.2f \n",havg[i]);
    for(int j=0; j<i; j++){
       if (a[i]>max) {
           max = a[i];
       }
       if (a[i]<min) {
           min = a[i];
       }
    }
    if(a[i]>havg[i-1]&&i!=0){
       break;
    }
}
printf("---Data Complete---\n");
printf("Max: %.0f\n", max);
printf("Min: %.0f\n", min);

这里的输出是：

Enter number : 24

Loop 0 Summation : 24 Half of Avg. : 12.00

Enter number : 12

Loop 1 Summation : 36 Half of Avg. : 9.00

Enter number : -5

Loop 2 Summation : 31 Half of Avg. : 5.17

Enter number : 9

Loop 3 Summation : 40 Half of Avg. : 5.00

---Data Complete---

Max: 24

Min: 9

我已经在 google 上查找数组中的最小值和最大值。我想我把事情搞砸了：

#include<stdio.h>
int main(){
float a[100],sum=0.0,avg,havg[100],min=0.0,max=0.0;
int i;
for(i=0; i!=-1;i++){
    printf("Enter number : ");
    scanf("%f",&a[i]);
    max = a[0];
    min = a[0];
    sum+=a[i];
    avg= sum/(i+1);
    havg[i]=avg/2;
    printf("Loop %d Summation : %.0f ",i+1,sum);
    printf("Half of Avg. : %.2f \n",havg[i]);
    if (a[i]>max){
      max = a[i];
        }
    if (a[i]<min){
      min = a[i];
        }
    if(a[i]>havg[i-1]&&i!=0){
       break;
    }
}
printf("---Data Complete---\n");
printf("Max: %.0f\n", max);
printf("Min: %.0f\n", min);
}

所以现在我用不同的数字测试（先从负数开始）

Enter number : -10

Loop 1 Summation : -10 Half of Avg. : -5.00 

Enter number : -90 

Loop 2 Summation : -100 Half of Avg. : -25.00 

Enter number : 30

Loop 3 Summation : -70 Half of Avg. : -11.67 

---Data Complete---

Max: 30

Min: -10

这真是令人困惑

Answer 1

请移动 min 和 max 初始化，这是在每个循环中完成的

#include<stdio.h>

int main(){
    float a[100],sum=0.0,avg,havg[100],min=0.0,max=0.0;
    int i;
    for(i=0; i!=-1;i++){
        printf("Enter number : ");
        scanf("%f",&a[i]);
        sum+=a[i];
        avg= sum/(i+1);
        havg[i]=avg/2;
        printf("Loop %d Summation : %.0f ",i+1,sum);
        printf("Half of Avg. : %.2f \n",havg[i]);
        if(i == 0) {
            max = a[0];             // moved to here
            min = a[0];
        }
        else {
            if (a[i]>max){
                max = a[i];
            }
            if (a[i]<min){
                min = a[i];
            }
            if(a[i]>havg[i-1]) {    // moved this too
                break;
            }
        }
    }
    printf("---Data Complete---\n");
    printf("Max: %.0f\n", max);
    printf("Min: %.0f\n", min);
}

程序输出：

Enter number : -10
Loop 1 Summation : -10 Half of Avg. : -5.00
Enter number : -90
Loop 2 Summation : -100 Half of Avg. : -25.00
Enter number : 30
Loop 3 Summation : -70 Half of Avg. : -11.67
---Data Complete---
Max: 30
Min: -90

我的最小部分没有显示真正的最小值

My minimum section isn't showing the real minimum

c

average

max

min