如何编写一个按商家组织然后按找到的重复项组织的查询？

Question

我正在寻找重复的 customerid 并希望按商家显示它们。我知道这需要自连接，但语法不正确。

此查询向我显示了重复项。

Select MerchId, CustId, Count(CustId) 
from Customers
Group by MerchId, CustId
Having Count(CustId)> 1

此查询向我显示了特定商家的所有重复项。

SELECT  c.MerchId, c.CustId 
FROM Customers c
WHERE CustId IN 
(SELECT c.CustId FROM Customers AS c
WHERE c.MerchId = @mid 
group by c.CustId having count(1) > 1)
and c.MerchId = @mid
order by CustId

但我想看到的信息显示为：

MerchId, CustId, Address, Phone     
1        01     
1        01     
1        02     
1        02     
1        03     
1        03     
2        01     
2        01     
2        02     
2        02

假设 n 个商家有 n 个顾客。提前致谢

Answer 1

您可以将查询加入 table:

select c.merchid, c.custid, c.address, c.phone 
from customers c inner join (
  select merchid, custid 
  from customers
  group by merchId, custId
  having count(custid)> 1
) g on g.merchid = c.merchid and g.custid = c.custid

或通过显式计算每一行（效率较低但更易于阅读）：

select c.merchid, c.custid, c.address, c.phone 
from customers c
where (
  select count(*) from customers
  where merchid = c.merchid and custid = c.custid
) > 1

如何编写一个按商家组织然后按找到的重复项组织的查询？

How does one write a query that organizes by merchant then by found duplicates?

sql

database

self-join