JSONObject 无法在 Volley 中转换为 JSONArray
JSONObject cannot be converted to JSONArray in Volley
还有我的代码
ArrayRequest = new JsonArrayRequest(JSON_URL, new Response.Listener<JSONArray>() {
@Override
public void onResponse(JSONArray response) {
JSONObject jsonObject = null;
for (int i = 0 ; i<response.length();i++) {
try {
// JSONObject jsonObject = (JSONObject) response.get(i);
jsonObject = response.getJSONObject(i);
JSONObject jsonObjectt = jsonObject.getJSONObject("search_result");
Users users = new Users();
users.setId(jsonObjectt.getString("id"));
users.setUser(jsonObjectt.getString("User"));
users.setName(jsonObjectt.getString("name"));
users.setWho(jsonObjectt.getString("who"));
users.setImage(jsonObjectt.getString("image"));
userlist.add(users);
}
catch (JSONException e) {
e.printStackTrace();
}
}
setRvadapter(userlist);
我无法从 api 获取任何数据,它说 JSONObject 无法在 android
中转换为 JSONArray
您正在使用 JsonArray 作为响应并且您的 Web 服务 return 是一个 jsonobject
new JsonObjectRequest
(Request.Method.GET, url, null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
JSONArray teachers = response.getJSONArray("search_result");
for(int i = 0; i < teachers.length() ; i++) {
// do what ever you want with
Teacher teacher = new Teacher();
// here is how to get name
teacher.setId(teachers.getJSONObject(i).getString("name"));
// do the rest like this.
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
// TODO: Handle error
}
});
还有我的代码
ArrayRequest = new JsonArrayRequest(JSON_URL, new Response.Listener<JSONArray>() {
@Override
public void onResponse(JSONArray response) {
JSONObject jsonObject = null;
for (int i = 0 ; i<response.length();i++) {
try {
// JSONObject jsonObject = (JSONObject) response.get(i);
jsonObject = response.getJSONObject(i);
JSONObject jsonObjectt = jsonObject.getJSONObject("search_result");
Users users = new Users();
users.setId(jsonObjectt.getString("id"));
users.setUser(jsonObjectt.getString("User"));
users.setName(jsonObjectt.getString("name"));
users.setWho(jsonObjectt.getString("who"));
users.setImage(jsonObjectt.getString("image"));
userlist.add(users);
}
catch (JSONException e) {
e.printStackTrace();
}
}
setRvadapter(userlist);
我无法从 api 获取任何数据,它说 JSONObject 无法在 android
中转换为 JSONArray您正在使用 JsonArray 作为响应并且您的 Web 服务 return 是一个 jsonobject
new JsonObjectRequest
(Request.Method.GET, url, null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
JSONArray teachers = response.getJSONArray("search_result");
for(int i = 0; i < teachers.length() ; i++) {
// do what ever you want with
Teacher teacher = new Teacher();
// here is how to get name
teacher.setId(teachers.getJSONObject(i).getString("name"));
// do the rest like this.
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
// TODO: Handle error
}
});