如何计算行之间的时间差

Question

我在 table 中有以下数据：

qincId   ID     lc1           lc2            Time                    SP
963     544 22.3000526428   73.1743087769   2019-03-31 17:00:46.000  15
965     544 22.2998828888   73.1746368408   2019-03-31 17:01:07.000  2
968     544 22.2998828888   73.1746368408   2019-03-31 17:01:40.000  2
997     544 22.3010215759   73.1744003296   2019-03-31 17:06:11.000  15
998     544 22.3011436462   73.1747131348   2019-03-31 17:06:21.000  17
1010    544 22.3034667969   73.1747512817   2019-03-31 17:08:04.000  0
1011    544 22.3032741547   73.1747512817   2019-03-31 17:08:03.000  0
1565    544 22.3032035828   73.1748123169   2019-03-31 18:45:26.000  0
1571    544 22.3028964996   73.1748123169   2019-03-31 18:46:03.000  16
1573    544 22.3023796082   73.1747131348   2019-03-31 18:46:21.000  15
1575    544 22.3021774292   73.1746444702   2019-03-31 18:46:37.000  0
1577    544 22.3019657135   73.1747665405   2019-03-31 18:46:50.000  15
1586    544 22.3009243011   73.1742477417   2019-03-31 18:47:33.000  5
1591    544 22.2998828888   73.1745300293   2019-03-31 18:48:19.000  5
1592    544 22.2998828888   73.1745300293   2019-03-31 18:48:28.000  5
1593    544 22.2998981476   73.1746063232   2019-03-31 18:48:29.000  4
1597    544 22.3000450134   73.1744232178   2019-03-31 18:49:08.000  0
1677    544 22.3000450134   73.1744232178   2019-03-31 19:03:28.000  0

现在我想计算从下一条记录到 sp = 0 的行之间的时间差。

预期输出：

qincId   ID     lc1           lc2            Time                    SP   TimeDiff (Minute)
963     544 22.3000526428   73.1743087769   2019-03-31 17:00:46.000  15     NULL
965     544 22.2998828888   73.1746368408   2019-03-31 17:01:07.000  2      NULL
968     544 22.2998828888   73.1746368408   2019-03-31 17:01:40.000  2      NULL
997     544 22.3010215759   73.1744003296   2019-03-31 17:06:11.000  15     NULL
998     544 22.3011436462   73.1747131348   2019-03-31 17:06:21.000  17     NULL
1010    544 22.3034667969   73.1747512817   2019-03-31 17:08:04.000  0       0.01 
1011    544 22.3032741547   73.1747512817   2019-03-31 17:08:03.000  0       97
1565    544 22.3032035828   73.1748123169   2019-03-31 18:45:26.000  0       1
1571    544 22.3028964996   73.1748123169   2019-03-31 18:46:03.000  16     NULL
1573    544 22.3023796082   73.1747131348   2019-03-31 18:46:21.000  15     NULL
1575    544 22.3021774292   73.1746444702   2019-03-31 18:46:37.000  0      0.21
1577    544 22.3019657135   73.1747665405   2019-03-31 18:46:50.000  15     NULL
1586    544 22.3009243011   73.1742477417   2019-03-31 18:47:33.000  5      NULL
1591    544 22.2998828888   73.1745300293   2019-03-31 18:48:19.000  5      NULL
1592    544 22.2998828888   73.1745300293   2019-03-31 18:48:28.000  5      NULL
1593    544 22.2998981476   73.1746063232   2019-03-31 18:48:29.000  4      NULL
1597    544 22.3000450134   73.1744232178   2019-03-31 18:49:08.000  0      14
1677    544 22.3000450134   73.1744232178   2019-03-31 19:03:28.000  0      NULL

所以基本上我只想计算以分钟为单位的时差。

我该怎么做？

Answer 1

你可以试试lag() sqlserver版本>=2012

select *, case when sp=0 then
datediff(second,time,lag(time) over(order by time)) else null end
from table_name

Answer 2

如果下一条记录是指具有大于当前时间的最小时间的行：

select t.*, 
  round(case 
    when t.sp = 0 then
      datediff(second, t.time,
        (select min(time) from tablename where time > t.time)
      ) 
    else null 
  end / 60.0, 2) timediff
from tablename t

如何计算行之间的时间差

How to calculate time difference between rows

sql

sql-server

sql-server-2008