如何在 Android Studio 中使用 u0423 代码解析 json 对象

Question

我不知道如何解析这个。

{
  "code": 1000,
  "result_msg": "Successful",
  "result": "{\"birthDateAsText\":\"1999-12-3100:00:00.0\",\"birthPlace\":\"\u0423\u0423\u0423\u0423\u0423\u0423\u0423\u0423\u0423\u0423\u0423,\u0423\u0423\u0423\u0423\u0423\u0423\u0423\u0423\u0423\",\"civilId\":\"123\",\"firstname\":\"\u0423\u0423\u0423\u0423\u0423\u0423\",\"gender\":\"\u0423\u0423\u0423\u0423\u0423\u0423\u0423\",\"lastname\":\"\u0423\u0423\u0423\u0423\u0423\u0423\u0423\u0423\u0423\u0423\u0423\",\"nationality\":\"\u0423\u0423\u0423\u0423\"}"
}

我试过了

 if (resultObject.getInt("code") == 1000) {
   JSONParse jsonParse = new JSONParse();
   JSONObject object = resultObject.getJSONObject("result");
   event.onSuccess(jsonParse.convertJson(object));
   }

其实我不知道如何解析和解码jsonobject。请帮助我

Answer 1

使用 UTF-8 解码您的回复

 try {
         resp = new String(Base64.decode(response.getBytes("UTF-8"), Base64.NO_WRAP), "UTF-8");
        } catch (UnsupportedEncodingException e) {
            // Suppress exception (unlikely to happen in prod)
            PbLogger.e("Encoding exception", "");
        }

Answer 2

试试这个：

private static String decodeUnicode(String theString) {
    char aChar;
    int len = theString.length();
    StringBuffer outBuffer = new StringBuffer(len);
    for (int x = 0; x < len;) {
        aChar = theString.charAt(x++);
        if (aChar == '\') {
            aChar = theString.charAt(x++);
            if (aChar == 'u') {
                // Read the xxxx
                int value = 0;
                for (int i = 0; i < 4; i++) {
                    aChar = theString.charAt(x++);
                    switch (aChar) {
                        case '0':
                        case '1':
                        case '2':
                        case '3':
                        case '4':
                        case '5':
                        case '6':
                        case '7':
                        case '8':
                        case '9':
                            value = (value << 4) + aChar - '0';
                            break;
                        case 'a':
                        case 'b':
                        case 'c':
                        case 'd':
                        case 'e':
                        case 'f':
                            value = (value << 4) + 10 + aChar - 'a';
                            break;
                        case 'A':
                        case 'B':
                        case 'C':
                        case 'D':
                        case 'E':
                        case 'F':
                            value = (value << 4) + 10 + aChar - 'A';
                            break;
                        default:
                            throw new IllegalArgumentException(
                                    "Malformed   \uxxxx   encoding.");
                    }

                }
                outBuffer.append((char) value);
            } else {
                if (aChar == 't')
                    aChar = '\t';
                else if (aChar == 'r')
                    aChar = '\r';
                else if (aChar == 'n')
                    aChar = '\n';
                else if (aChar == 'f')
                    aChar = '\f';
                outBuffer.append(aChar);
            }
        } else
            outBuffer.append(aChar);
    }
    return outBuffer.toString();
}

使用：

JSONObject object = resultObject.getJSONObject("result");
System.out.println("Birthday: "+object.getString("birthPlace"))

如何在 Android Studio 中使用 u0423 代码解析 json 对象

How to parse json object with u0423 code in Android Studio

java

parsing

android

json

decode