pyodbc 使用参数名称调用存储过程；数据类型问题

Question

当运行 cursor_insert.execute(sql,params) 时，即使我的源和目标数据库 table 将数据定义为 float、nvarchar 和 nvarchar 以及我的存储过程。

是否将我的参数设置为名为 'params' 的新变量导致数据类型发生这种变化？如果是这样，我该如何解决？（在阅读一些 Python 文档时，它不应该更改数据类型，对吗？）

# Create cursor associated with connection
cursor=conn.cursor()
cursor_select = conn.cursor()
cursor_insert = conn.cursor()

if conn:
    print('***** Connected to DCPWDBS289 *****')

select_str="SELECT TOP 5 Incident_ID,Incident_Type,Priority FROM 
incidents_all WHERE incidents_all.Status NOT IN ('Closed','Resolved')"

cursor_select.execute(select_str)

while True:

    row = cursor_select.fetchone()
    if not row:
        break
    print(' Row:     ', row)

    IncIncident_ID      = row[0]    # Float
    IncIncident_Type    = row[1]    # Str
    IncPriority         = row[2]    # Str

    sql = """EXEC ITSM.dbo.ITSM_LOAD @IncIncident_ID=?, 
    @IncIncident_Type=?,@IncPriority=?"""

    params = ('IncIncident_ID','IncIncident_Type','IncPriority')

    cursor_insert.execute(sql,params)

del cursor_insert
cursor.commit()
conn.close()

Answer 1

您没有传递 parameter 值，而是传递字符串文字，试试这个：

# Create cursor associated with connection
cursor=conn.cursor()
cursor_select = conn.cursor()
cursor_insert = conn.cursor()

if conn:
    print('***** Connected to DCPWDBS289 *****')

select_str="SELECT TOP 5 Incident_ID,Incident_Type,Priority FROM 
incidents_all WHERE incidents_all.Status NOT IN ('Closed','Resolved')"

cursor_select.execute(select_str)

while True:

    row = cursor_select.fetchone()
    if not row:
        break
    print(' Row:     ', row)

    IncIncident_ID      = row[0]    # Float
    IncIncident_Type    = row[1]    # Str
    IncPriority         = row[2]    # Str

    sql = """EXEC ITSM.dbo.ITSM_LOAD @IncIncident_ID=?, 
    @IncIncident_Type=?,@IncPriority=?"""

    params = (IncIncident_ID, IncIncident_Type, IncPriority)

    cursor_insert.execute(sql,params)

del cursor_insert
cursor.commit()
conn.close()

pyodbc 使用参数名称调用存储过程；数据类型问题

pyodbc call stored procedure with parameter name; data type issue

python

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