将 LINQ 查询的枚举限制为一个
Restricting the enumerations of LINQ queries to One Only
我有一个不应多次枚举的 LINQ 查询,我想避免错误地枚举它两次。我可以使用任何扩展方法来确保我免受此类错误的影响吗?我在想这样的事情:
var numbers = Enumerable.Range(1, 10).OnlyOnce();
Console.WriteLine(numbers.Count()); // shows 10
Console.WriteLine(numbers.Count()); // throws InvalidOperationException: The query cannot be enumerated more than once.
我想要此功能的原因是因为我有一个可枚举的任务,旨在逐步实例化和 运行 任务,同时在控制下缓慢枚举。我已经错误地 运行 任务两次,因为我忘记了它是一个不同的枚举而不是
一个数组。
var tasks = Enumerable.Range(1, 10).Select(n => Task.Run(() => Console.WriteLine(n)));
Task.WaitAll(tasks.ToArray()); // Lets wait for the tasks to finish...
Console.WriteLine(String.Join(", ", tasks.Select(t => t.Id))); // Lets see the completed task IDs...
// Oups! A new set of tasks started running!
Enumerables 枚举,故事结束。您只需要调用 ToList
或 ToArray
// this will enumerate and start the tasks
var tasks = Enumerable.Range(1, 10)
.Select(n => Task.Run(() => Console.WriteLine(n)))
.ToList();
// wait for them all to finish
Task.WaitAll(tasks.ToArray());
Console.WriteLine(String.Join(", ", tasks.Select(t => t.Id)));
Hrm 如果你想要并行
Parallel.For(0, 100, index => Console.WriteLine(index) );
或者如果您正在使用异步和等待模式
public static async Task DoWorkLoads(IEnumerable <Something> results)
{
var options = new ExecutionDataflowBlockOptions
{
MaxDegreeOfParallelism = 50
};
var block = new ActionBlock<Something>(MyMethodAsync, options);
foreach (var result in results)
block.Post(result);
block.Complete();
await block.Completion;
}
...
public async Task MyMethodAsync(Something result)
{
await SomethingAsync(result);
}
更新,既然你在寻找控制最大并发度的方法,你可以使用这个
public static async Task<IEnumerable<Task>> ExecuteInParallel<T>(this IEnumerable<T> collection,Func<T, Task> callback,int degreeOfParallelism)
{
var queue = new ConcurrentQueue<T>(collection);
var tasks = Enumerable.Range(0, degreeOfParallelism)
.Select(async _ =>
{
while (queue.TryDequeue(out var item))
await callback(item);
})
.ToArray();
await Task.WhenAll(tasks);
return tasks;
}
I want to avoid enumerating it twice by mistake.
您可以使用一个在枚举两次时抛出异常的集合来包装该集合。
例如:
using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;
namespace ConsoleApp8
{
public static class EnumExtension
{
class OnceEnumerable<T> : IEnumerable<T>
{
IEnumerable<T> col;
bool hasBeenEnumerated = false;
public OnceEnumerable(IEnumerable<T> col)
{
this.col = col;
}
public IEnumerator<T> GetEnumerator()
{
if (hasBeenEnumerated)
{
throw new InvalidOperationException("This collection has already been enumerated.");
}
this.hasBeenEnumerated = true;
return col.GetEnumerator();
}
IEnumerator IEnumerable.GetEnumerator()
{
return GetEnumerator();
}
}
public static IEnumerable<T> OnlyOnce<T>(this IEnumerable<T> col)
{
return new OnceEnumerable<T>(col);
}
}
class Program
{
static void Main(string[] args)
{
var col = Enumerable.Range(1, 10).OnlyOnce();
var colCount = col.Count(); //first enumeration
foreach (var c in col) //second enumeration
{
Console.WriteLine(c);
}
}
}
}
Rx 当然是控制并行度的一个选项。
var query =
Observable
.Range(1, 10)
.Select(n => Observable.FromAsync(() => Task.Run(() => new { Id = n })));
var tasks = query.Merge(maxConcurrent: 3).ToArray().Wait();
Console.WriteLine(String.Join(", ", tasks.Select(t => t.Id)));
我有一个不应多次枚举的 LINQ 查询,我想避免错误地枚举它两次。我可以使用任何扩展方法来确保我免受此类错误的影响吗?我在想这样的事情:
var numbers = Enumerable.Range(1, 10).OnlyOnce();
Console.WriteLine(numbers.Count()); // shows 10
Console.WriteLine(numbers.Count()); // throws InvalidOperationException: The query cannot be enumerated more than once.
我想要此功能的原因是因为我有一个可枚举的任务,旨在逐步实例化和 运行 任务,同时在控制下缓慢枚举。我已经错误地 运行 任务两次,因为我忘记了它是一个不同的枚举而不是 一个数组。
var tasks = Enumerable.Range(1, 10).Select(n => Task.Run(() => Console.WriteLine(n)));
Task.WaitAll(tasks.ToArray()); // Lets wait for the tasks to finish...
Console.WriteLine(String.Join(", ", tasks.Select(t => t.Id))); // Lets see the completed task IDs...
// Oups! A new set of tasks started running!
Enumerables 枚举,故事结束。您只需要调用 ToList
或 ToArray
// this will enumerate and start the tasks
var tasks = Enumerable.Range(1, 10)
.Select(n => Task.Run(() => Console.WriteLine(n)))
.ToList();
// wait for them all to finish
Task.WaitAll(tasks.ToArray());
Console.WriteLine(String.Join(", ", tasks.Select(t => t.Id)));
Hrm 如果你想要并行
Parallel.For(0, 100, index => Console.WriteLine(index) );
或者如果您正在使用异步和等待模式
public static async Task DoWorkLoads(IEnumerable <Something> results)
{
var options = new ExecutionDataflowBlockOptions
{
MaxDegreeOfParallelism = 50
};
var block = new ActionBlock<Something>(MyMethodAsync, options);
foreach (var result in results)
block.Post(result);
block.Complete();
await block.Completion;
}
...
public async Task MyMethodAsync(Something result)
{
await SomethingAsync(result);
}
更新,既然你在寻找控制最大并发度的方法,你可以使用这个
public static async Task<IEnumerable<Task>> ExecuteInParallel<T>(this IEnumerable<T> collection,Func<T, Task> callback,int degreeOfParallelism)
{
var queue = new ConcurrentQueue<T>(collection);
var tasks = Enumerable.Range(0, degreeOfParallelism)
.Select(async _ =>
{
while (queue.TryDequeue(out var item))
await callback(item);
})
.ToArray();
await Task.WhenAll(tasks);
return tasks;
}
I want to avoid enumerating it twice by mistake.
您可以使用一个在枚举两次时抛出异常的集合来包装该集合。
例如:
using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;
namespace ConsoleApp8
{
public static class EnumExtension
{
class OnceEnumerable<T> : IEnumerable<T>
{
IEnumerable<T> col;
bool hasBeenEnumerated = false;
public OnceEnumerable(IEnumerable<T> col)
{
this.col = col;
}
public IEnumerator<T> GetEnumerator()
{
if (hasBeenEnumerated)
{
throw new InvalidOperationException("This collection has already been enumerated.");
}
this.hasBeenEnumerated = true;
return col.GetEnumerator();
}
IEnumerator IEnumerable.GetEnumerator()
{
return GetEnumerator();
}
}
public static IEnumerable<T> OnlyOnce<T>(this IEnumerable<T> col)
{
return new OnceEnumerable<T>(col);
}
}
class Program
{
static void Main(string[] args)
{
var col = Enumerable.Range(1, 10).OnlyOnce();
var colCount = col.Count(); //first enumeration
foreach (var c in col) //second enumeration
{
Console.WriteLine(c);
}
}
}
}
Rx 当然是控制并行度的一个选项。
var query =
Observable
.Range(1, 10)
.Select(n => Observable.FromAsync(() => Task.Run(() => new { Id = n })));
var tasks = query.Merge(maxConcurrent: 3).ToArray().Wait();
Console.WriteLine(String.Join(", ", tasks.Select(t => t.Id)));