Scala - 处理 "multiple overloaded alternatives of method ... define default arguments"

Scala - handling "multiple overloaded alternatives of method ... define default arguments"

假设我有这样的设置:

sealed trait Annotation {
    def notes : Seq[String]
}

trait Something extends Annotation{
    //do something funny
}

case class A(val i:Int)(val notes:Seq[String] = Nil) extends Something
object A{
    def apply(a:A)(notes:Seq[String] = Nil):A = A(a.i)(notes)
}

case class B(val b:Boolean)(val notes:Seq[String] = Nil) extends Something
object B{
    def apply(b:B)(notes:Seq[String] = Nil):B = B(b.b)(notes)
}

case class C(val s:String)(val notes:Seq[String] = Nil) extends Something
object C{
    def apply(c:C)(notes:Seq[String] = Nil) :C = C(c.s)(notes)
}

尝试compile这将导致

Main.scala:10: error: in object A, multiple overloaded alternatives of method apply define
default arguments.
object A{
       ^

Main.scala:15: error: in object B, multiple overloaded alternatives of method apply define
default arguments.
object B{
       ^

Main.scala:20: error: in object C, multiple overloaded alternatives of method apply define
default arguments.
object C{
       ^
three errors found

我已经阅读了 this,所以我至少知道为什么会这样,但是我不知道我应该如何解决这个问题。

当然,一种可能性是简单地省略默认值并强制客户端在不存储注释时提供 Nil,但是有更好的解决方案吗?

我的第一个猜测是简单地使默认参数显式化:

case class A(i: Int)(val notes: Seq[String]) extends Something
object A {
  def apply(i: Int): A = new A(i)(Nil)
  def apply(a: A)(notes: Seq[String]): A = new A(a.i)(notes)
  def apply(a: A): A = new A(a.i)(Nil)
}

但是,现在,由于柯里化,您只有函数 Int => AInt => Seq[String] => A(以及 A => A 的类似函数)在范围内具有相同的名称。


如果您不使用柯里化,您可以手动定义重载方法:

case class B(b: Boolean, notes: Seq[String]) extends Something

object B {
  def apply(b: Boolean): B = B(b, Nil)
  def apply(b: B, notes: Seq[String] = Nil): B = B(b.b, notes)
}

但是,由于 notes 现在是与 b 相同的参数列表的一部分,因此 toString 等 case-class 方法的行为发生了变化。

println(B(true))                  // B(true,List())
println(B(true, List("hello")))   // B(true,List(hello))
println(B(B(false)))              // B(false,List())

最后,为了更接近地模仿原始行为,您可以实现自己的 equalshashCodetoStringunapply 方法:

class C(val s:String, val notes:Seq[String] = Nil) extends Something {

  override def toString = s"C($s)"

  override def equals(o: Any) = o match {
    case C(`s`) => true
    case _ => false
  }

  override def hashCode = s.hashCode
}

object C{
  def apply(s: String, notes: Seq[String]) = new C(s, notes)
  def apply(s: String): C = C(s, Nil)
  def apply(c:C, notes:Seq[String] = Nil): C = C(c.s, notes)
  def unapply(c: C): Option[String] = Some(c.s)
}

示例:

val c1 = C("hello")
val c2 = C("hello", List("world"))
println(c1)                 // C(hello)
println(c2)                 // C(hello)
println(c1 == c2)           // true
c1 match {                  // hello
  case C(n) => println(n)
  case _ =>
}