无法将类型 'Int' 的值转换为预期的参数类型 '(inout UnsafeMutableBufferPointer<_>, inout Int) throws -> Void'

Question

这一行 var machine = [CChar](_unsafeUninitializedCapacity: size, initializingWith: 0) 抛出错误。

错误信息：

Cannot convert value of type 'Int' to expected argument type '(inout UnsafeMutableBufferPointer<_>, inout Int) throws -> Void'

这是我的代码：

struct MailTemplate {
    let destination = "test@gmail.com"
    let subject = "Test"
    let body:String

    init(){
        let appVersion: String! = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") as? String
        var platform: String {
            var size: Int = 0
            sysctlbyname("hw.machine", nil, &size, nil, 0)
            var machine = [CChar](_unsafeUninitializedCapacity: size, initializingWith: 0)
            sysctlbyname("hw.machine", &machine, &size, nil, 0)
            return String.fromCString(machine)!
        }
        body = "Email Body"
    }
}

Answer 1

inout 参数是那些将被我们传递给它的函数修改的参数。因此，您需要将其作为 &size.

传递

Answer 2

我得到了答案，

initializingWith: {_,_ in}

像那样：

var machine = [CChar](_unsafeUninitializedCapacity: size, initializingWith: {_,_ in})

无法将类型 'Int' 的值转换为预期的参数类型 '(inout UnsafeMutableBufferPointer<_>, inout Int) throws -> Void'

Cannot convert value of type 'Int' to expected argument type '(inout UnsafeMutableBufferPointer<_>, inout Int) throws -> Void'

ios

swift4