如何在不刷新页面且不使用 ajax 的情况下成功 post 后更新页面内容
How to update page content after success post in a form without page refresh and not using ajax
在 cshtml 文件中,有一个表单,我想更新数据而不刷新整个页面,只刷新该表单。
After Updation of form user spam count form value image is here
我只是在表单标签中输入操作方法,输入标签值传递给控制器并更新该值,但整个页面都刷新了,但我只想刷新那个表单。Befor Update any value
使用 Ajax Post 你可以 post 数据而无需刷新整个页面。
示例:
Html
<h2>PostDataForm</h2>
<div class="card mb-3">
<div class="card-header">
<i class="fas fa-table"></i>
Form 1
</div>
<div class="card-body">
<div class="form-group">
<input type="text" id="Email1" name="Email1" class="form-control"
placeholder="Email address" >
</div>
<input type="button" id="BtnForm1" class="btn btn-primary btn-block"
value="Submit" />
</div>
</div>
<div class="card mb-3">
<div class="card-header">
<i class="fas fa-table"></i>
Form 2
</div>
<div class="card-body">
<div class="form-group">
<div class="form-label-group">
<input type="text" id="Email2" name="Email2" class="form-control"
placeholder="Email address" >
</div>
</div>
<input type="button" id="BtnForm2" class="btn btn-primary btn-block"
value="Submit" />
</div>
</div>
<div class="card mb-3">
<div class="card-header">
<i class="fas fa-table"></i>
Form 3
</div>
<div class="card-body">
<div class="form-group">
<div class="form-label-group">
<input type="text" id="Email3" name="Email3" class="form-control"
placeholder="Email address">
</div>
</div>
<input type="button" id="BtnForm3" class="btn btn-primary btn-block"
value="Submit" />
</div>
</div>
JS
<script src="/vendor/jquery/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#BtnForm1").click(function () {
if ($("#Email1").val() != '') {
$.ajax({
type: 'POST',
url: '/User/PostDataForm1',
// dataType: 'json',
data: { email: $("#Email1").val() },
success: function() {
alert("Form 1 submitted successfully!");
},
error: function (ex) {
alert("ex");
}
});
} else {
alert("Please Form 1 email address");
}
});
});
</script>
控制器
public ActionResult PostDataForm() {
return View();
}
[HttpPost]
public ActionResult PostDataForm1(string email) {
//update your data
return Json("Success", JsonRequestBehavior.AllowGet);
}
类似写剩余表格post方法
在 cshtml 文件中,有一个表单,我想更新数据而不刷新整个页面,只刷新该表单。 After Updation of form user spam count form value image is here 我只是在表单标签中输入操作方法,输入标签值传递给控制器并更新该值,但整个页面都刷新了,但我只想刷新那个表单。Befor Update any value
使用 Ajax Post 你可以 post 数据而无需刷新整个页面。
示例:
Html
<h2>PostDataForm</h2>
<div class="card mb-3">
<div class="card-header">
<i class="fas fa-table"></i>
Form 1
</div>
<div class="card-body">
<div class="form-group">
<input type="text" id="Email1" name="Email1" class="form-control"
placeholder="Email address" >
</div>
<input type="button" id="BtnForm1" class="btn btn-primary btn-block"
value="Submit" />
</div>
</div>
<div class="card mb-3">
<div class="card-header">
<i class="fas fa-table"></i>
Form 2
</div>
<div class="card-body">
<div class="form-group">
<div class="form-label-group">
<input type="text" id="Email2" name="Email2" class="form-control"
placeholder="Email address" >
</div>
</div>
<input type="button" id="BtnForm2" class="btn btn-primary btn-block"
value="Submit" />
</div>
</div>
<div class="card mb-3">
<div class="card-header">
<i class="fas fa-table"></i>
Form 3
</div>
<div class="card-body">
<div class="form-group">
<div class="form-label-group">
<input type="text" id="Email3" name="Email3" class="form-control"
placeholder="Email address">
</div>
</div>
<input type="button" id="BtnForm3" class="btn btn-primary btn-block"
value="Submit" />
</div>
</div>
JS
<script src="/vendor/jquery/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#BtnForm1").click(function () {
if ($("#Email1").val() != '') {
$.ajax({
type: 'POST',
url: '/User/PostDataForm1',
// dataType: 'json',
data: { email: $("#Email1").val() },
success: function() {
alert("Form 1 submitted successfully!");
},
error: function (ex) {
alert("ex");
}
});
} else {
alert("Please Form 1 email address");
}
});
});
</script>
控制器
public ActionResult PostDataForm() {
return View();
}
[HttpPost]
public ActionResult PostDataForm1(string email) {
//update your data
return Json("Success", JsonRequestBehavior.AllowGet);
}
类似写剩余表格post方法