我想更改时间计算格式（django模型，虚拟字段）

Question

模型字段代码是这个

    created = models.DateTimeField(auto_now=True)


    @property
    def now_diff(self):
        return timezone.now() - self.created

我有一个关于使用虚拟字段的django时间循环的问题

当前时间循环输出为5:26:34.349728

但是我想5:26:34

有办法吗？

谢谢你告诉我~！

我改成了

    @property
    def now_diff(self):
        s=timezone.now() - self.created
        hours, remainder = divmod(s, 3600)
        minutes, seconds = divmod(remainder, 60)
        return '{:02}:{:02}:{:02}'.format(int(hours), int(minutes), int(seconds))

但是错误


TypeError: 'Todo' object is not subscriptable

TypeError: unsupported operand type(s) for divmod(): 'datetime.timedelta' and 'int'

Answer 1

也许你可以这样尝试（主要是从this答案中复制粘贴）：

@property
def now_diff(self):
    time_delta = timezone.now() - self.created
    s = time_delta.seconds
    hours, remainder = divmod(s, 3600)
    minutes, seconds = divmod(remainder, 60)
    return '{:02}:{:02}:{:02}'.format(int(hours), int(minutes), int(seconds))

Answer 2

从timedelta中减去微秒

from datetime import timedelta


class MyModel(models.Model):
    ...
    created = models.DateTimeField(auto_now=True)

    @property
    def now_diff(self):
        <b>delta = timezone.now() - self.created
        return str(delta - timedelta(microseconds=delta.microseconds))</b>

为了更易读的解决方案，

from datetime import timedelta


<b>def chop_microseconds(delta):
    return delta - timedelta(microseconds=delta.microseconds)</b>

class MyModel(models.Model):
    ...
    created = models.DateTimeField(auto_now=True)

    @property
    def now_diff(self):
        return <b>str(chop_microseconds(timezone.now() - self.created))</b>

一些BG东西

如果我们查看 timedelta 的 Source code of __str__() 函数 class,

....
if self._microseconds:
    s = s + ".%06d" % self._microseconds
...

转换 timedelta 对象的字符串表示形式。
所以，这里我们从 timedelta 中减去 microsecond 从而解决了问题:)

我想更改时间计算格式（django模型，虚拟字段）

I want to change the time calculation format (django models, virtual field)

django

field

django-models

datetime-format

一些BG东西