使用 Python 将列表转换为字典

Question

有一个值列表：

list_inside = ["de:14612:1","de:14612:21","de:14612:17","de:14612:16"]

为什么我得到的不是 {'from': '1', 'to': '16'} {'from': '16', 'to': '16'}。我的代码做错了什么？

keys = ["from", "to"]

list_inside = ["de:14612:1","de:14612:21","de:14612:17","de:14612:16"]

for i in list_inside[::len(list_inside)-1]:
    result = dict((key, i.join(i.split(":", 2)[2::1])) for key in keys)

print(result)

Answer 1

使用

keys = ["from", "to"]

list_inside = ["de:14612:1","de:14612:21","de:14612:17","de:14612:16"]
result = {}    #Declare empty dict
for key, v in zip(keys, list_inside[::len(list_inside)-1]):  
    result.update({key: v.split(":", 2)[-1])})  #Use dict.update to update the required values. 

print(result)

输出：

{'to': '16', 'from': '1'}

您当前的方法是覆盖 result 变量。

Answer 2

你在一个循环中做了 result = 几次。

很明显，这里只有最后一次迭代才有效

Answer 3

这段代码得到了您所期望的结果。 -1 做了简单的代码。

keys = ["from", "to"]

list_inside = ["de:14612:1","de:14612:21","de:14612:17","de:14612:16"]

result = {}
result[keys[0]] = list_inside[0].split(':')[2]
result[keys[1]] = list_inside[-1].split(':')[2]

print (result)

使用 Python 将列表转换为字典

Transforming list into dictionary with Python

transformation

python-3.x