尝试在 gridview 中添加 link

Trying to add a link within a gridview

我已经创建了一个 sql 数据库,其中一个名为 "Link" 的列有网站 url,用于我网站内和网站外的网站。例如,我有一份 link 的 Geico 保险。问题是当我将此列添加到我的 gridview 时,它只显示网站的 url。我需要它成为我可以点击并在新页面中显示的网站的 link,我只想要 "website" 这个词作为 link。

<asp:GridView id="GridView1" runat="server" AutoGenerateColumns="False" BackColor="White" BorderColor="#999999" BorderStyle="None" BorderWidth="1px" CellPadding="3" DataSourceID="apps2" GridLines="Vertical" AllowSorting="True">
    <AlternatingRowStyle BackColor="#DCDCDC" />
    <Columns>
        <asp:HyperLinkField HeaderText="Link" Text="Website" DataNavigateUrlFields="Link" DataNavigateUrlFormatString="{0}" target=_blank/>
        </asp:HyperLinkField>
        <asp:BoundField DataField="Source" HeaderText="Source" SortExpression="Source">
        </asp:BoundField>
        <asp:BoundField DataField="Name" HeaderText="Name" SortExpression="Name">
        </asp:BoundField>
        <asp:BoundField DataField="Address" HeaderText="Address" SortExpression="Address">
        </asp:BoundField>
        <asp:BoundField DataField="City" HeaderText="City" SortExpression="City">
        </asp:BoundField>
        <asp:BoundField DataField="Primary_Number" HeaderText="Phone Number" SortExpression="Primary_Number">
        </asp:BoundField>
        <asp:BoundField DataField="Backup_Number" HeaderText="Backup Number" SortExpression="Backup_Number">
        </asp:BoundField>
        <asp:BoundField DataField="Fax_Number" HeaderText="Fax Number" SortExpression="Fax_Number">
        </asp:BoundField>
        <asp:BoundField DataField="Alarm_Reset_Code" HeaderText="Alarm Reset Code" SortExpression="Alarm_Reset_Code">
        </asp:BoundField>
        <asp:BoundField DataField="First_Contact_Name" HeaderText="1st Contact Name" SortExpression="First_Contact_Name">
        </asp:BoundField>
        <asp:BoundField DataField="First_Contact_Number" HeaderText="1st Contact #" SortExpression="First_Contact_Number">
        </asp:BoundField>
        <asp:BoundField DataField="Second_Contact_Name" HeaderText="2nd Contact Name" SortExpression="Second_Contact_Name">
        </asp:BoundField>
        <asp:BoundField DataField="Second_Contact_Number" HeaderText="2nd Contact #" SortExpression="Second_Contact_Number">
        </asp:BoundField>
        <asp:BoundField DataField="Third_Contact_Name" HeaderText="3rd Contact Name" SortExpression="Third_Contact_Name">
        </asp:BoundField>
        <asp:BoundField DataField="Third_Contact_Number" HeaderText="3rd Contact #" SortExpression="Third_Contact_Number">
        </asp:BoundField>
        <asp:BoundField DataField="Notes" HeaderText="Notes" SortExpression="Notes">
        </asp:BoundField>
        <asp:BoundField DataField="Modified" HeaderText="Date Modified" SortExpression="Modified">
        </asp:BoundField>
    </Columns>

当我使用这个脚本时,gridview 没有在我的网站上启动。我收到服务器错误,错误中突出显示的是 hyperlink 字段的行。

Gridview 最好使用 <ItemTemplate> 来显示网站链接。这样您就可以完全自定义超链接列的 UI/Design。

示例:

<ItemTemplate>
        <a href="<%# Bind("Link") %>" target="_blank">Website</a>
    </ItemTemplate>