我想同时赋值2个变量,它们在从另一个文件导入的函数中
I want to assign 2 variables at the same time, which are in the function imported from another file
我想同时赋值2个变量,它们在从另一个文件导入的函数中。
THIS IS THIS FUNCTION
def counter(init=[0]):
init[0] += 1
return init[0]
_____________________________________________
THIS IS ANOTHER SCRIPT
from Include.new_var import counter
first_letter = []
second_letter = []
def license_plate():
global first_letter, second_letter
characters = string.ascii_uppercase
prices_for_letters = dict(zip(characters, range(1, len(characters) + 1)))
print(prices_for_letters)
实际结果:
counter(first_letter), counter(second_letter) = random.choice(list(prices_for_letters.items()))
^
SyntaxError: can't assign to function call
预期结果:
new variable
我想自动生成新的变量来存储随机选择的值。
能否说明一下您之后打算做什么?这里你只是想调用函数两次。
还请提供预期结果等。
但是:
- 首先,选择只会 return 一项 - 您需要两项。
- 其次,只需将选择语句放入您的函数调用中:
counter(random.choice(list(prices_for_letters.items())))
counter(random.choice(list(prices_for_letters.items())))
Assumptions:
1) Your function name seems to imply that you want to create a license plate.
2) Going through your profile, I see that you are from Poland so i assume you are trying to create a random license generator for vehicles in Poland.
3) A quick google search reveals that Poland license plates are 7 characters long with 2 or 3 initial chars followed by numbers.
def counter(some_char, draft_plate= []):
draft_plate.append(str(some_char))
return draft_plate
def license_plate():
final_license_plate = []
characters = string.ascii_uppercase
numbers = range(0,10)
prices_for_letters = dict(zip(characters, range(1, len(characters) + 1)))
prices_for_numbers = dict(zip(numbers, range(1, len(numbers)+1)))
numofchars = random.randint(2,3)
for i in range(0,numofchars):
counter(random.choice(list(prices_for_letters.keys())), final_license_plate)
final_license_plate.append(' ')
for j in range(numofchars,7):
counter(random.choice(list(prices_for_numbers.keys())), final_license_plate)
print(final_license_plate)
license_plate()
我想同时赋值2个变量,它们在从另一个文件导入的函数中。
THIS IS THIS FUNCTION
def counter(init=[0]):
init[0] += 1
return init[0]
_____________________________________________
THIS IS ANOTHER SCRIPT
from Include.new_var import counter
first_letter = []
second_letter = []
def license_plate():
global first_letter, second_letter
characters = string.ascii_uppercase
prices_for_letters = dict(zip(characters, range(1, len(characters) + 1)))
print(prices_for_letters)
实际结果:
counter(first_letter), counter(second_letter) = random.choice(list(prices_for_letters.items()))
^
SyntaxError: can't assign to function call
预期结果:
new variable
我想自动生成新的变量来存储随机选择的值。
能否说明一下您之后打算做什么?这里你只是想调用函数两次。
还请提供预期结果等。
但是:
- 首先,选择只会 return 一项 - 您需要两项。
- 其次,只需将选择语句放入您的函数调用中:
counter(random.choice(list(prices_for_letters.items())))
counter(random.choice(list(prices_for_letters.items())))
Assumptions:
1) Your function name seems to imply that you want to create a license plate.
2) Going through your profile, I see that you are from Poland so i assume you are trying to create a random license generator for vehicles in Poland.
3) A quick google search reveals that Poland license plates are 7 characters long with 2 or 3 initial chars followed by numbers.
def counter(some_char, draft_plate= []):
draft_plate.append(str(some_char))
return draft_plate
def license_plate():
final_license_plate = []
characters = string.ascii_uppercase
numbers = range(0,10)
prices_for_letters = dict(zip(characters, range(1, len(characters) + 1)))
prices_for_numbers = dict(zip(numbers, range(1, len(numbers)+1)))
numofchars = random.randint(2,3)
for i in range(0,numofchars):
counter(random.choice(list(prices_for_letters.keys())), final_license_plate)
final_license_plate.append(' ')
for j in range(numofchars,7):
counter(random.choice(list(prices_for_numbers.keys())), final_license_plate)
print(final_license_plate)
license_plate()