从数组中查找唯一值
Find Unique Value from a array
我有一个多维数组,我需要查找数组是否具有相同的 'brand' 属性值,然后 return 它的 ID。
我尝试通过一些数组函数,但没有用。
我尝试了什么:
1)
$backwards = array_reverse($attribute);
echo '<pre>';
$last_item = NULL;
$i = 0;
foreach ($backwards as $current_item) {
if ($last_item === $current_item[$i]['value']) {
echo '<pre>'; print_r($current_item[$i]['value']);
}
$last_item = $current_item[$i]['value'];
echo '<pre>'; print_r($last_item);
$i++;
}
2)
$j = 1;
$i = 0;
foreach ($attributeValues as $attributeData) {
foreach ($attribute as $value) {
if($value[$i]['value'] == $value[$j]['value']) {
echo '<pre>'; print_r($value); die();
}
$j++;
}
}
我的所有解决方案都不起作用,请帮助。
[0] => Array
(
[0] => Array
(
[name] => brand
[value] => 54
[id] => 5251
[price] => 15000.0000
)
[1] => Array
(
[name] => model
[value] => 1200
[id] => 5251
[price] => 15000.0000
)
)
[1] => Array
(
[0] => Array
(
[name] => brand
[value] => 54
[id] => 5250
[price] => 15000.0000
)
[1] => Array
(
[name] => model
[value] => 1200
[id] => 5250
[price] => 12000.0000
)
)
[2] => Array
(
[0] => Array
(
[name] => brand
[value] => 89
[id] => 518
[price] => 100.0000
)
[1] => Array
(
[name] => model
[value] => 12
[id] => 518
[price] => 100
)
)
如果第一个数组的 [name]=>brand
和 [name]=>model
值与第二个数组的值相同,则 return [id]
.
您可以使用 foreach
并遍历数组
$res = [];
foreach($arr as $k => $v){
if($v[0]['name'] == $v[1]['name'])
$res[$v[0]['name']] = $v[0]['id'];
}
如果你想匹配索引value
试试这个
foreach($arr as $k => $v){
if($v[0]['value'] == $v[1]['value'])
$res[] = $v[0]['id'];
}
你需要两个for循环。
$result =[];
foreach ($arr as $key => $value) {
foreach($value as $v){
$result[$v['name']][] = $v['id'];
}
}
$result = array_map("array_unique", $result); // to make it unique
print_r($result);
// if you want to check ids for brand
//print_r($result['brand']);
输出:
Array
(
[brand] => Array
(
[0] => 5251
[1] => 5250
[3] => 518
)
[model] => Array
(
[0] => 5251
[1] => 518
)
)
Demo.
编辑
然后你可以按它的名称和值对其进行分组
$result =[];
foreach ($arr as $key => $value) {
foreach($value as $v){
$result[$v['name']."|".$v['value']][] = $v['id'];
}
}
$result = array_map("array_unique", $result);
print_r($result);die;
Demo.
我有一个多维数组,我需要查找数组是否具有相同的 'brand' 属性值,然后 return 它的 ID。
我尝试通过一些数组函数,但没有用。
我尝试了什么:
1)
$backwards = array_reverse($attribute);
echo '<pre>';
$last_item = NULL;
$i = 0;
foreach ($backwards as $current_item) {
if ($last_item === $current_item[$i]['value']) {
echo '<pre>'; print_r($current_item[$i]['value']);
}
$last_item = $current_item[$i]['value'];
echo '<pre>'; print_r($last_item);
$i++;
}
2)
$j = 1;
$i = 0;
foreach ($attributeValues as $attributeData) {
foreach ($attribute as $value) {
if($value[$i]['value'] == $value[$j]['value']) {
echo '<pre>'; print_r($value); die();
}
$j++;
}
}
我的所有解决方案都不起作用,请帮助。
[0] => Array
(
[0] => Array
(
[name] => brand
[value] => 54
[id] => 5251
[price] => 15000.0000
)
[1] => Array
(
[name] => model
[value] => 1200
[id] => 5251
[price] => 15000.0000
)
)
[1] => Array
(
[0] => Array
(
[name] => brand
[value] => 54
[id] => 5250
[price] => 15000.0000
)
[1] => Array
(
[name] => model
[value] => 1200
[id] => 5250
[price] => 12000.0000
)
)
[2] => Array
(
[0] => Array
(
[name] => brand
[value] => 89
[id] => 518
[price] => 100.0000
)
[1] => Array
(
[name] => model
[value] => 12
[id] => 518
[price] => 100
)
)
如果第一个数组的 [name]=>brand
和 [name]=>model
值与第二个数组的值相同,则 return [id]
.
您可以使用 foreach
并遍历数组
$res = [];
foreach($arr as $k => $v){
if($v[0]['name'] == $v[1]['name'])
$res[$v[0]['name']] = $v[0]['id'];
}
如果你想匹配索引value
试试这个
foreach($arr as $k => $v){
if($v[0]['value'] == $v[1]['value'])
$res[] = $v[0]['id'];
}
你需要两个for循环。
$result =[];
foreach ($arr as $key => $value) {
foreach($value as $v){
$result[$v['name']][] = $v['id'];
}
}
$result = array_map("array_unique", $result); // to make it unique
print_r($result);
// if you want to check ids for brand
//print_r($result['brand']);
输出:
Array
(
[brand] => Array
(
[0] => 5251
[1] => 5250
[3] => 518
)
[model] => Array
(
[0] => 5251
[1] => 518
)
)
Demo.
编辑
然后你可以按它的名称和值对其进行分组
$result =[];
foreach ($arr as $key => $value) {
foreach($value as $v){
$result[$v['name']."|".$v['value']][] = $v['id'];
}
}
$result = array_map("array_unique", $result);
print_r($result);die;
Demo.