Laravel 匹配前缀后所有内容的路由

Question

我正在尝试匹配 URL 中的路径，如下所示

我的 HTTP 请求

http://localhost/myprefix/extra/x/x/x/x/x/2/3/2/

routes.php

Route::group(
    ['prefix' => 'myprefix'],
    function () {
        Route::get('extra/{path}', ['as' => 'myprefix.one', 'uses' => 'MyController@index']);
        Route::get('extraOTher/{path}', ['as' => 'myprefix.two', 'uses' => 'MyController@indexOther']);
    }
);

MyController.php

public function index($path)
{
    // $path should be extra/x/x/x/x/x/2/3/2/
}

这一直给我错误

NotFoundHttpException in RouteCollection.php line 145:

我怎样才能让它工作？我在某处读到过 :any 和 :all 但我也无法使它们正常工作。

Answer 1

有点老套。

Routes.php:

Route::group(
    ['prefix' => 'myprefix'],
    function () {
        Route::get('extra/{path}', ['as' => 'myprefix.one', 'uses' => 'MyController@index']);
        Route::get('extraOTher/{path}', ['as' => 'myprefix.two', 'uses' => 'MyController@indexOther']);
    }
);

添加模式。

Route::pattern('path', '[a-zA-Z0-9-/]+');

现在它将捕获所有路由。

Controller.php:

public function index($path)
{
    echo $path; // outputs x/x/x/2/3/4/ whatever there is. 

    // To get the prefix with all the segements,

    echo substr(parse_url(\Request::url())['path'],1);
}

不优雅。但它应该可以解决问题。

Laravel 匹配前缀后所有内容的路由

Laravel routes matching everything after prefix

laravel

laravel-4

laravel-routing

laravel-5

Routes.php:

Controller.php: