无法解决与 Temp Table 的归类冲突错误

Question

我正在尝试列出数据库中丢失的一些记录，as described in my unanswered question here

我现在正尝试用应该检查的数据填充临时 table，并将其与数据库中的数据进行比较。我的查询如下：

create table #Temp
(
    Component nvarchar(50),
    AssetType nvarchar(50)
)

Insert Into #Temp (Component, AssetType) VALUES
  ('0990.LB00.000.06', '0738.D100.M00.60_03.03'),
  ('0738.D100.L00.55', '9211.D108.D07.01_02.02');


WITH DBD AS (
            Select distinct C.Code Comp, AT.Code AssetType From astComponents C
            Join astAssetTypes AT ON AT.Id = C.AssetTypeId
            Where (C.Code = '0990.LB00.000.06' And AT.Code = '0738.D100.M00.60_03.03') OR (C.Code = '0738.D100.L00.55' And AT.Code = '9211.D108.D07.01_02.02')
            ),
     Compare AS 
            (
            Select T.* FROM #Temp T
            Left Join DBD ON DBD.Comp = T.Component AND DBD.AssetType = T.AssetType
            Where DBD.Comp is null
            )

Select * From Compare

预期输出如下，因为数据库中不存在这个组件-资产类型组合

Component             Asset Type
0990.LB00.000.06      0738.D100.M00.60_03.03

但是，我遇到了错误

Msg 468, Level 16, State 9, Line 22
Cannot resolve the collation conflict between "SQL_Latin1_General_CP1_CI_AS" and "Latin1_General_BIN" in the equal to operation.

Answer 1

排序规则定义了一种比较字符串的方法。每当您在字符串类型之间进行比较（排序也需要比较）时，您需要应用相同的标准，这就是归类类型。

CREATE TABLE #StringLatin (
    String VARCHAR(100) COLLATE SQL_Latin1_General_CP1_CI_AS)

CREATE TABLE #StringBIN (
    String VARCHAR(100) COLLATE Latin1_General_BIN)

SELECT
    'Oops!!!'
FROM
    #StringLatin AS L
    INNER JOIN #StringBIN AS B ON L.String = B.String

Msg 468, Level 16, State 9, Line 5 Cannot resolve the collation conflict between "Latin1_General_BIN" and "SQL_Latin1_General_CP1_CI_AS" in the equal to operation.

这里的问题是 L.String = B.String，因为两者都是使用不同的排序规则类型创建的。

您可以通过更改 table 的创建语句中的排序规则（以便它匹配您稍后加入的任何一个）或直接在 SELECT 内的比较中解决此问题。

SELECT
    'Works'
FROM
    #StringLatin AS L
    INNER JOIN #StringBIN AS B ON L.String = B.String COLLATE SQL_Latin1_General_CP1_CI_AS

默认排序规则可能因服务器而异，它会影响所有未指定特定排序规则的 table，这在使用不同的数据库时可能会带来麻烦。要查找默认排序规则，您可以使用：

SELECT SERVERPROPERTY('collation');

无法解决与 Temp Table 的归类冲突错误

Cannot resolve the collation conflict error with Temp Table

sql

sql-server

common-table-expression