游戏按数组路径走

Question

我正在编写一种算法，用于以给定速度迭代数组的元素。我用它在我找到的路径数组中遍历游戏地图上的单元格。

我需要当用新数组调用新函数时，最后一个函数调用停止工作。

这将用于在单击鼠标时沿路径移动。现在，如果我们调用第一个函数，它会沿着路径走，但如果在路径结束之前，用新路径再次调用该函数，那么它们都将继续改变当前坐标。

对象必须在它第一次调用函数时到达的地方中断它的路径，并在第二次函数调用中继续它的路径。

下面是它现在如何工作的示例代码：

let coord = {x:0,y:0}
 
 let goByPath = (path=[],coord={})=>{
    let i = 0;
    pathIteration(i,path,coord)
  }

  let pathIteration = (i,path,coord)=>{

    if(i++<path.length){
      setTimeout(()=>{
        coord = path[i-1];
        console.log(coord);
        pathIteration(i,path,coord);
      },500);
    }
    return i;
  };
  
path1 = [{x:0,y:1},{x:1,y:1},{x:1,y:2},{x:2,y:2}];

path2 = [{x:1,y:3},{x:1,y:4},{x:1,y:5}];

goByPath(path1, coord);

setTimeout(()=>{
    goByPath(path2, coord);  
},900);

现在输出到控制台：

{
  "x": 0,
  "y": 1
}
{
  "x": 1,
  "y": 1
}
{
  "x": 1,
  "y": 3
}
{
  "x": 1,
  "y": 2
}
{
  "x": 1,
  "y": 4
}
{
  "x": 2,
  "y": 2
}
{
  "x": 1,
  "y": 5
}

需要输出：

{
  "x": 0,
  "y": 1
}
{
  "x": 1,
  "y": 1
}
{
  "x": 1,
  "y": 3
}
{
  "x": 1,
  "y": 4
}
{
  "x": 1,
  "y": 5
}

Answer 1

你只需要clearTimeouthttps://developer.mozilla.org/en-US/docs/Web/API/WindowOrWorkerGlobalScope/clearTimeout

let coord = { x: 0, y: 0 };

let myTimeout;

let goByPath = (path = [], coord = {}) => {
  let i = 0;
  clearTimeout(myTimeout); // stop previous calls
  pathIteration(i, path, coord);
}

let pathIteration = (i, path, coord) => {
  rect(coord);
  if (i++ < path.length) {
    myTimeout = setTimeout(() => { // store reference to timeout
      coord = path[i - 1];
      pathIteration(i, path, coord);
    }, 500);
  }
  return i;
};

/* canvas grid for display purposes */

var canvas = document.querySelector('canvas');
var ctx = canvas.getContext('2d');
var n = 10;
var size = Math.min(innerWidth, innerHeight);
var u = size / n;

var draw = function() {
  size = Math.min(innerWidth, innerHeight);
  u = size / n;
  canvas.width = size;
  canvas.height = size;

  for (var y = 0; y < n; y++) {
    for (var x = 0; x < n; x++) {
      ctx.strokeStyle = '#000';
      ctx.strokeRect(x * u, y * u, u, u);
    }
  }
};
draw();
var rect = (coord) => {
  ctx.fillStyle = '#888';
  ctx.fillRect(coord.x * u, coord.y * u, u, u);
};

/* example */

var path1 = [{x:0,y:1},{x:1,y:1},{x:1,y:2},{x:2,y:2}];
goByPath(path1, coord);


var path2 = [{x:1,y:3},{x:1,y:4},{x:1,y:5}];
setTimeout(() => { goByPath(path2, coord); }, 1600);

body {
  margin: 0;
  display: grid;
  place-content: center;
}

<canvas></canvas>

Answer 2

你可以有一个简单的多线程实现如下：

let coord = { x: 0, y: 0 }
let coordLock = null

let goByPath = (path = [], coord = {}) => {
  const newLock = Math.random()
  coordLock = newLock
  pathIteration(0, path, coord, newLock)
}

let pathIteration = (i, path, coord, lock) => {
  if (lock !== coordLock) return i
  if (i++ < path.length) {
    setTimeout(() => {
      coord = path[i - 1]
      console.log(coord)
      pathIteration(i, path, coord, lock)
    }, 500)
  }
  return i
}

const path1 = [{ x: 0, y: 1 }, { x: 1, y: 1 }, { x: 1, y: 2 }, { x: 2, y: 2 }]
const path2 = [{ x: 1, y: 3 }, { x: 1, y: 4 }, { x: 1, y: 5 }]

goByPath(path1, coord)
setTimeout(() => goByPath(path2, coord), 900)

话虽这么说，但我认为此实现对于此类任务来说很薄弱。对于此类任务，您应该具有适当的面向对象结构。如果此代码库增长，您将来肯定会得到意想不到的结果要将重要的东西更改为坐标，您不能依赖副作用和全局定义的对象

游戏按数组路径走

Game walk by path in array

javascript

game-development