Select 字符串范围之间的数据

Select data between string range

我有一个 table Employee,

_________________________________
Id | name    |      salary                    
______________________________
1  | John    |   [1300 - 2000] 
_______________________________
2  | Aby     |   [600 - 1000] 
________________________________
3  | Mike    |   [1000 - 1500] 

工资栏是Nvarchar

我想要 SQL 中的查询/函数/SP,如果我搜索 1400,输出应该如下所示

Id | name    |      salary                    
________________________________
1  | John    |   [1300 - 2000] 
_______________________________
3  | Mike    |   [1000 - 1500] 

提前致谢。

您不应将范围存储在一列中。但如果你不能改变它,那就是解决方案:

SELECT  [Id] , name, 
      ,[salary] 
  FROM [Test Database].[dbo].[test] where 
1700 >= RTRIM(LTRIM(SUBSTRING(salary,0, CHARINDEX('-',salary)))) 
and 1700 <=  RTRIM(LTRIM(SUBSTRING(salary, CHARINDEX('-', salary) + 1, LEN(salary))))

您需要提取数值,然后转换为数值类型:

declare @mySalary money;
set  @mySalary = 1400;

with Employee(ID, Name, Salary ) as
(
 select 1,'John','[1300 - 2000]' union all
 select 2,'Aby','[600 - 1000]'   union all
 select 3,'Mike','[1000 - 1500]'
), e2 as
(
select SUBSTRING(Salary,PATINDEX('%[0-9]%', Salary),CHARINDEX('-',Salary)-2) as Salary1,
       SUBSTRING(Salary,CHARINDEX('-',Salary)+1,CHARINDEX(']',Salary)-CHARINDEX('-',Salary)-1) as Salary2,
       e.*
  from Employee e
)
select ID, Name, Salary
  from e2
 where @mySalary between cast(Salary1 as money) and cast(Salary2 as money);

ID  Name    Salary
1   John    [1300 - 2000]
3   Mike    [1000 - 1500]

Demo

试试这个查询:

declare @tbl table (id int, name varchar(15), salary varchar(20));
declare @mySalary int = 1400;

insert into @tbl 
 select 1,'John','[1300 - 2000]' union all
 select 2,'Aby','[600 - 1000]'   union all
 select 3,'Mike','[1000 - 1500]'

select id, name, salary from (
    select id, name, salary,
           convert(int, substring(salary, openBrcktIdx + 1, hyphenIdx - openBrcktIdx - 2)) lowerBound,
           convert(int, substring(salary, hyphenIdx + 2, closeBrcktIdx - hyphenIdx - 2)) upperBound
    from (
        select *,
               charindex('-', salary) hyphenIdx,
               charindex('[', salary) openBrcktIdx,
               charindex(']', salary) closeBrcktIdx
        from @tbl
    ) t
) t where @mySalary between lowerBound and upperBound

声明@var1 int =1400

select * 来自 (select *,replace(SUBSTRING(salary,0,CHARINDEX('-',salary,0)),'[','') as Splitted1, 替换(SUBSTRING(薪水,CHARINDEX('-',薪水,0)+ 1,len(薪水)-1),']','')作为Splitted2 来自员工 ) 作为 t1 其中@var1>=Splitted1 和@var1<=Splitted2

https://rextester.com/l/sql_server_online_compiler