How to fix 'Uncaught Error: Call to a member function fetch_assoc() on integer'
How to fix 'Uncaught Error: Call to a member function fetch_assoc() on integer'
我运行正在查询以接收参加比赛的电子邮件列表,通知他们比赛已经结束以及比赛何时结束运行。
我查看了代码,看不出哪里失败了。我正在绑定 ID,并且在执行查询时我也收到了正确的数据。
这是我正在 运行ning 的函数。
function notifyEntrants($id, $sendMsg){
$connect = db();
$stmt = $connect->prepare('SELECT DISTINCT CONCAT(`payer`.`FirstName`, " ", `payer`.`LastName`) AS "Name", `payer`.`Email` AS "Email" FROM `transaction` INNER JOIN `payer` ON `payer`.`DrawID` = `transaction`.`DrawID` WHERE `transaction`.`DrawID` = ?;');
$stmt->bind_param("i", $id);
$stmt->execute();
$result = $stmt->get_result();
$drawTitle = getTitle($id);
while($row = $result->fetch_assoc()){
$email = $row['Email'];
$name = $row['Name'];
// Create the Transport
$transport = (new Swift_SmtpTransport('smtp.gmail.com', 465, 'ssl'))
->setUsername(SITE_EMAIL)
->setPassword(MAIL_PASS)
;
$sendMsg .= "<br><br><a href=" . SITE_URL . "entries?id=".$id.">Click here</a> to see the entry list for this draw.";
// Create the Mailer using your created Transport
$mailer = new Swift_Mailer($transport);
// Create a message
$message = (new Swift_Message("Live draw confirmation for $drawTitle"))
->setFrom([SITE_EMAIL => SITE_NAME])
->setTo([$email => $name])
->setBody($sendMsg, 'text/html');
// Send the message
$result = $mailer->send($message);
}
}
//echo notifyEntrants(15, "test");
在 var_dump 我得到了这个 array(2) { ["Name"]=> string(6) "Aidan " ["Email"]=> string(22) "adonnelly759@qub.ac.uk" }
这正是我所期待的。只有一个电子邮件地址和用户名。
然而这最终导致了错误:"Fatal error: Uncaught Error: Call to a member function fetch_assoc() on integer".
提前致谢,抱歉,如果这很简单,我只是无法理解这个问题的按钮。
您正在用此行覆盖 SQL 结果:
$result = $mailer->send($message);
您需要为其中之一指定一个不同的名称。
我运行正在查询以接收参加比赛的电子邮件列表,通知他们比赛已经结束以及比赛何时结束运行。
我查看了代码,看不出哪里失败了。我正在绑定 ID,并且在执行查询时我也收到了正确的数据。
这是我正在 运行ning 的函数。
function notifyEntrants($id, $sendMsg){
$connect = db();
$stmt = $connect->prepare('SELECT DISTINCT CONCAT(`payer`.`FirstName`, " ", `payer`.`LastName`) AS "Name", `payer`.`Email` AS "Email" FROM `transaction` INNER JOIN `payer` ON `payer`.`DrawID` = `transaction`.`DrawID` WHERE `transaction`.`DrawID` = ?;');
$stmt->bind_param("i", $id);
$stmt->execute();
$result = $stmt->get_result();
$drawTitle = getTitle($id);
while($row = $result->fetch_assoc()){
$email = $row['Email'];
$name = $row['Name'];
// Create the Transport
$transport = (new Swift_SmtpTransport('smtp.gmail.com', 465, 'ssl'))
->setUsername(SITE_EMAIL)
->setPassword(MAIL_PASS)
;
$sendMsg .= "<br><br><a href=" . SITE_URL . "entries?id=".$id.">Click here</a> to see the entry list for this draw.";
// Create the Mailer using your created Transport
$mailer = new Swift_Mailer($transport);
// Create a message
$message = (new Swift_Message("Live draw confirmation for $drawTitle"))
->setFrom([SITE_EMAIL => SITE_NAME])
->setTo([$email => $name])
->setBody($sendMsg, 'text/html');
// Send the message
$result = $mailer->send($message);
}
}
//echo notifyEntrants(15, "test");
在 var_dump 我得到了这个 array(2) { ["Name"]=> string(6) "Aidan " ["Email"]=> string(22) "adonnelly759@qub.ac.uk" }
这正是我所期待的。只有一个电子邮件地址和用户名。
然而这最终导致了错误:"Fatal error: Uncaught Error: Call to a member function fetch_assoc() on integer".
提前致谢,抱歉,如果这很简单,我只是无法理解这个问题的按钮。
您正在用此行覆盖 SQL 结果:
$result = $mailer->send($message);
您需要为其中之一指定一个不同的名称。