Laravel

Question

我需要帮助，我使用以下代码请求文件：

$client = new Client(['verify' => false]);

$response = $client->request('GET', 'https://url', [
    'headers' => [
        'Authorization' => 'Bearer token'
    ]
]);

$mime = $response->getHeader('Content-Type');
$binary = $response->getBody();

我收到的答案如下：

Content-Type: image/jpeg or other appropriate media type
Content-Length: content-size

binary-media-data

我的问题是：如何存储这个文件？我在互联网上找不到任何东西...

Answer 1

使用 Storage facade 创建一个新文件。

Storage::put('file.jpg', $binary)

如果 Mime 类型可以更改，则获取文件，然后使用 PutFile：

use Illuminate\Http\File;
use Illuminate\Support\Facades\Storage;

$client = new Client(['verify' => false]);

$tmpfile = tempnam(sys_get_temp_dir(),'dl');

$response = $client->request('GET', $url, [
    'headers' => [
        'Authorization' => 'Bearer token'
    ],
    'sink' => $tmpfile
]);

$filename = Storage::putFile('dir_within_storage', new File($tmpfile));

如果文件名始终可靠并且您不担心重复，那么您可以使用 Guzzle 直接输入：

$client = new Client(['verify' => false]);

$filePath = basename($url);

$response = $client->request('GET', $url, [
    'headers' => [
        'Authorization' => 'Bearer token'
    ],
    'sink' => storage_path('dir_within_storage/'.$filePath)
]);

Laravel - 如何从 Guzzle 保存二进制文件

Laravel - How to save binary from Guzzle

php

guzzle