类型 'AreaData' 不符合协议 'Encodable'
Type 'AreaData' does not conform to protocol 'Encodable'
当我为 JSON 文件制作模型时,出现了这两个错误。
1) 我在 AreaData 结构中遇到了一致错误
2) “AnyObject
不能用作符合协议 Decodable
的类型,因为 Decodable
具有静态要求”初始化程序中的错误。
我尝试了几种方法,但找不到正确的解决方案。我怎样才能为这个nested/complexJSON制作一个合适的模型?
这是我的 JSON 文件。此数据嵌套
[
{
"ID": "01",
"Name": "Area 01",
"parentId": null,
"sublevel": [
{
"ID": "01-01",
"Name": "Building 01",
"On": "",
"Off": "",
"parentId": "01",
"sublevel": [
{
"ID": "01-01-01",
"Name": "Flat 01",
"On": "",
"Off": "",
"parentId": "01-01",
"sublevel": []
}
]
},
{
"ID": "01-02",
"Name": "Building 02",
"On": "01",
"Off": "03",
"parentId": "01",
"sublevel": [
{
"ID": "01-02-01",
"Name": "Flat 01",
"On": "",
"Off": "",
"parentId": "01-02",
"sublevel": []
},
{
"ID": "01-02-02",
"Name": "Flat 02",
"On": "01",
"Off": "02",
"parentId": "01-02",
"sublevel": []
},
{
"ID": "01-02-03",
"Name": "Flat 03",
"On": "02",
"Off": "12",
"parentId": "01-02",
"sublevel": [
{
"ID": "01-02-03-01",
"Name": "Room 01",
"On": "",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-02",
"Name": "Room 02",
"On": "",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-03",
"Name": "Room 03",
"On": "02",
"Off": "03",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-04",
"Name": "Room 04",
"On": "",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-05",
"Name": "Room 05",
"On": "01",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
}
]
},
{
"ID": "01-02-04",
"Name": "Flat 04",
"On": "12",
"Off": "03",
"parentId": "01-02",
"sublevel": []
},
{
"ID": "01-02-05",
"Name": "Flat 05",
"On": "02",
"Off": "",
"parentId": "01-02",
"sublevel": []
}
]
},
{
"ID": "01-03",
"Name": "Building 03",
"On": "02",
"Off": "01",
"parentId": "01",
"sublevel": []
},
{
"ID": "01-04",
"Name": "Building 04",
"On": "",
"Off": "",
"parentId": "01",
"sublevel": []
}
]
}
]
这是我的模型class
import Foundation
struct AreaData : Codable {
let iD : String?
let name : String?
let parentId : AnyObject?
let sublevel : [Sublevel]?
enum CodingKeys: String, CodingKey {
case iD = "ID"
case name = "Name"
case parentId = "parentId"
case sublevel = "sublevel"
}
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
iD = try values.decodeIfPresent(String.self, forKey: .iD)
name = try values.decodeIfPresent(String.self, forKey: .name)
parentId = try values.decodeIfPresent(AnyObject.self, forKey: .parentId)
sublevel = try values.decodeIfPresent([Sublevel].self, forKey: .sublevel)
}
}
struct Sublevel : Codable {
let on : String?
let iD : String?
let name : String?
let off : String?
let parentId : String?
let sublevel : [Sublevel]?
enum CodingKeys: String, CodingKey {
case on = "On"
case iD = "ID"
case name = "Name"
case off = "Off"
case parentId = "parentId"
case sublevel = "sublevel"
}
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
on = try values.decodeIfPresent(String.self, forKey: .on)
iD = try values.decodeIfPresent(String.self, forKey: .iD)
name = try values.decodeIfPresent(String.self, forKey: .name)
off = try values.decodeIfPresent(String.self, forKey: .off)
parentId = try values.decodeIfPresent(String.self, forKey: .parentId)
sublevel = try values.decodeIfPresent([Sublevel].self, forKey: .sublevel)
}
}
试试这个,
struct AreaDataModel: Codable {
let id, name: String
let parentID: String? // AnyObject can't conform to Encodable protocol .
let sublevel: [Sublevel]
enum CodingKeys: String, CodingKey {
case id = "ID"
case name = "Name"
case parentID = "parentId"
case sublevel
}
}
// MARK: - Sublevel
struct Sublevel: Codable {
let id, name, on, off: String
let parentID: String
let sublevel: [Sublevel]
enum CodingKeys: String, CodingKey {
case id = "ID"
case name = "Name"
case on = "On"
case off = "Off"
case parentID = "parentId"
case sublevel
}
}
typealias AreaData = [AreaDataModel]
I recommend this tool simple and fast .
问题是由于 AnyObject
。 Codabe
不支持 Any
或 AnyObject
之类的内容。您需要明确指定类型。
在您添加的JSON响应中,parentId
是null
或String
。所以,你可以使用 String?
作为它的类型,即
struct AreaData : Codable {
let parentId : String? //here.....
//rest of the code....
}
此外,如果 属性,则无需在 enum CodingKeys
中明确指定 case
的 rawValue
key 完全匹配。所以struct AreaData
中的CodingKeys
一定是,
enum CodingKeys: String, CodingKey {
case iD = "ID"
case name = "Name"
case parentId, sublevel
}
此外,init(from decoder: Decoder)
不是必需的。这是因为您没有在其中进行任何特定的解析。直接解析将由 Codable
本身处理。
所以,struct AreaData
应该是这样的,
struct AreaData : Codable {
let iD : String?
let name : String?
let parentId : String?
let sublevel : [Sublevel]?
enum CodingKeys: String, CodingKey {
case iD = "ID"
case name = "Name"
case parentId, sublevel
}
}
也对 struct Sublevel
进行类似的更改。
此外,仅当您想要对数据进行编码和解码时才使用Codable
。如果您想要单一功能,即 编码或解码 ,请改用 Encodable
或 Decodable
。
建议:
由于 AreaData
和 Sublevel
包含几乎相同类型的数据,您可以使用单个 struct
到 decode
即 JSON,即
struct AreaData: Decodable {
let iD : String?
let name : String?
let parentId : String?
let sublevel : [AreaData]?
let on : String?
let off : String?
enum CodingKeys: String, CodingKey {
case iD = "ID"
case name = "Name"
case on = "On"
case off = "Off"
case parentId, sublevel
}
}
当我为 JSON 文件制作模型时,出现了这两个错误。
1) 我在 AreaData 结构中遇到了一致错误
2) “AnyObject
不能用作符合协议 Decodable
的类型,因为 Decodable
具有静态要求”初始化程序中的错误。
我尝试了几种方法,但找不到正确的解决方案。我怎样才能为这个nested/complexJSON制作一个合适的模型?
这是我的 JSON 文件。此数据嵌套
[
{
"ID": "01",
"Name": "Area 01",
"parentId": null,
"sublevel": [
{
"ID": "01-01",
"Name": "Building 01",
"On": "",
"Off": "",
"parentId": "01",
"sublevel": [
{
"ID": "01-01-01",
"Name": "Flat 01",
"On": "",
"Off": "",
"parentId": "01-01",
"sublevel": []
}
]
},
{
"ID": "01-02",
"Name": "Building 02",
"On": "01",
"Off": "03",
"parentId": "01",
"sublevel": [
{
"ID": "01-02-01",
"Name": "Flat 01",
"On": "",
"Off": "",
"parentId": "01-02",
"sublevel": []
},
{
"ID": "01-02-02",
"Name": "Flat 02",
"On": "01",
"Off": "02",
"parentId": "01-02",
"sublevel": []
},
{
"ID": "01-02-03",
"Name": "Flat 03",
"On": "02",
"Off": "12",
"parentId": "01-02",
"sublevel": [
{
"ID": "01-02-03-01",
"Name": "Room 01",
"On": "",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-02",
"Name": "Room 02",
"On": "",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-03",
"Name": "Room 03",
"On": "02",
"Off": "03",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-04",
"Name": "Room 04",
"On": "",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-05",
"Name": "Room 05",
"On": "01",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
}
]
},
{
"ID": "01-02-04",
"Name": "Flat 04",
"On": "12",
"Off": "03",
"parentId": "01-02",
"sublevel": []
},
{
"ID": "01-02-05",
"Name": "Flat 05",
"On": "02",
"Off": "",
"parentId": "01-02",
"sublevel": []
}
]
},
{
"ID": "01-03",
"Name": "Building 03",
"On": "02",
"Off": "01",
"parentId": "01",
"sublevel": []
},
{
"ID": "01-04",
"Name": "Building 04",
"On": "",
"Off": "",
"parentId": "01",
"sublevel": []
}
]
}
]
这是我的模型class
import Foundation
struct AreaData : Codable {
let iD : String?
let name : String?
let parentId : AnyObject?
let sublevel : [Sublevel]?
enum CodingKeys: String, CodingKey {
case iD = "ID"
case name = "Name"
case parentId = "parentId"
case sublevel = "sublevel"
}
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
iD = try values.decodeIfPresent(String.self, forKey: .iD)
name = try values.decodeIfPresent(String.self, forKey: .name)
parentId = try values.decodeIfPresent(AnyObject.self, forKey: .parentId)
sublevel = try values.decodeIfPresent([Sublevel].self, forKey: .sublevel)
}
}
struct Sublevel : Codable {
let on : String?
let iD : String?
let name : String?
let off : String?
let parentId : String?
let sublevel : [Sublevel]?
enum CodingKeys: String, CodingKey {
case on = "On"
case iD = "ID"
case name = "Name"
case off = "Off"
case parentId = "parentId"
case sublevel = "sublevel"
}
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
on = try values.decodeIfPresent(String.self, forKey: .on)
iD = try values.decodeIfPresent(String.self, forKey: .iD)
name = try values.decodeIfPresent(String.self, forKey: .name)
off = try values.decodeIfPresent(String.self, forKey: .off)
parentId = try values.decodeIfPresent(String.self, forKey: .parentId)
sublevel = try values.decodeIfPresent([Sublevel].self, forKey: .sublevel)
}
}
试试这个,
struct AreaDataModel: Codable {
let id, name: String
let parentID: String? // AnyObject can't conform to Encodable protocol .
let sublevel: [Sublevel]
enum CodingKeys: String, CodingKey {
case id = "ID"
case name = "Name"
case parentID = "parentId"
case sublevel
}
}
// MARK: - Sublevel
struct Sublevel: Codable {
let id, name, on, off: String
let parentID: String
let sublevel: [Sublevel]
enum CodingKeys: String, CodingKey {
case id = "ID"
case name = "Name"
case on = "On"
case off = "Off"
case parentID = "parentId"
case sublevel
}
}
typealias AreaData = [AreaDataModel]
I recommend this tool simple and fast .
问题是由于 AnyObject
。 Codabe
不支持 Any
或 AnyObject
之类的内容。您需要明确指定类型。
在您添加的JSON响应中,parentId
是null
或String
。所以,你可以使用 String?
作为它的类型,即
struct AreaData : Codable {
let parentId : String? //here.....
//rest of the code....
}
此外,如果 属性,则无需在 enum CodingKeys
中明确指定 case
的 rawValue
key 完全匹配。所以struct AreaData
中的CodingKeys
一定是,
enum CodingKeys: String, CodingKey {
case iD = "ID"
case name = "Name"
case parentId, sublevel
}
此外,init(from decoder: Decoder)
不是必需的。这是因为您没有在其中进行任何特定的解析。直接解析将由 Codable
本身处理。
所以,struct AreaData
应该是这样的,
struct AreaData : Codable {
let iD : String?
let name : String?
let parentId : String?
let sublevel : [Sublevel]?
enum CodingKeys: String, CodingKey {
case iD = "ID"
case name = "Name"
case parentId, sublevel
}
}
也对 struct Sublevel
进行类似的更改。
此外,仅当您想要对数据进行编码和解码时才使用Codable
。如果您想要单一功能,即 编码或解码 ,请改用 Encodable
或 Decodable
。
建议:
由于 AreaData
和 Sublevel
包含几乎相同类型的数据,您可以使用单个 struct
到 decode
即 JSON,即
struct AreaData: Decodable {
let iD : String?
let name : String?
let parentId : String?
let sublevel : [AreaData]?
let on : String?
let off : String?
enum CodingKeys: String, CodingKey {
case iD = "ID"
case name = "Name"
case on = "On"
case off = "Off"
case parentId, sublevel
}
}