"detail": "Method \"GET\"不允许。" Django 休息框架

Question

我知道这个问题可能是重复的，但我已经尝试了很多解决方案，但无法理解任何一个。我完全按照本教程进行操作，但我在 'userlist' 页面上收到此错误。其他一切都很好。有人可以指出错误是什么吗？

class UserList(APIView):
"""
Create a new user. It's called 'UserList' because normally we'd have a get
method here too, for retrieving a list of all User objects.
"""

permission_classes = (permissions.AllowAny,)
http_method_names = ['get', 'head']

def post (self, request, format=None):
    self.http_method_names.append("GET")

    serializer = UserSerializerWithToken(data=request.data)
    if serializer.is_valid():
        serializer.save()
        return Response(serializer.data, status=status.HTTP_201_CREATED)
    return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

编辑： urls.py

from django.urls import include, path
from classroom.views.classroom import current_user, UserList
from .views import classroom, suppliers, teachers
urlpatterns = [path('', classroom.home, name='home'),
               path('current_user/', current_user),
               path('users/', UserList.as_view()),

编辑：

仍然收到此错误，

Answer 1

您需要将 GET 端点 url 添加到您的 urls.py 才能使用 GET 请求。您的 urls.py 中缺少 GET url，只需像这样编辑您的 urls.py：

# urls.py

from django.urls import include, path
from classroom.views.classroom import current_user, UserList
from .views import classroom, suppliers, teachers

urlpatterns = [
               path('', classroom.home, name='home'),
               path('current_user/', current_user),
               path('users/', UserList.as_view()),
               path('users/<int:pk>/', UserList.as_view()),
              ]

并且您需要在 UserList 视图中实施 get 方法，例如：

# views.py

class UserList(APIView):
    """
    Create a new user. It's called 'UserList' because normally we'd have a get
    method here too, for retrieving a list of all User objects.
    """

    permission_classes = (permissions.AllowAny,)
    http_method_names = ['get', 'head']


    def get(self, request, format=None):
        users = User.objects.all()
        serializer = UserSerializerWithToken(users, many=True)
        return Response(serializer.data)

    def post(self, request, format=None):
        self.http_method_names.append("GET")

        serializer = UserSerializerWithToken(data=request.data)
        if serializer.is_valid():
            serializer.save()
            return Response(serializer.data, status=status.HTTP_201_CREATED)
        return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

Answer 2

基本上问题是，在您看来，没有为 GET 请求定义的功能。所以你可以添加它，像这样：

class UserList(APIView):
    permission_classes = (permissions.AllowAny,)
    http_method_names = ['get', 'head', 'post']

    def get(self, request, *args, **kwargs):
        serializer = UserSerializerWithToken(User.objects.all(), many=True)
        return Response(serializer.data, status=status.HTTP_200_OK)

    def post (self, request, format=None):
        self.http_method_names.append("GET")
        serializer = UserSerializerWithToken(data=request.data)
        if serializer.is_valid():
            serializer.save()
            return Response(serializer.data, status=status.HTTP_201_CREATED)
        return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

或者您可以子类化 UserList 来自 ListAPIView 的视图。

仅供参考，permission_classes 不适用于 APIView。您需要使用 GenericAPIView 或任何其他通用视图才能拥有这些功能。

Answer 3

我遇到了同样的问题，但我注意到在我的 views.py 中，我有

renderer_class = api_settings.DEFAULT_RENDERER_CLASSES

我更正为：

renderer_classes = api_settings.DEFAULT_RENDERER_CLASSES

它对我有用。

"detail": "Method \"GET\"不允许。" Django 休息框架

"detail": "Method \"GET\" not allowed." Django Rest Framework

python

api

django

http-post

django-rest-framework