为什么当我尝试写入文件时会出现奇怪的字符?
Why do strange characters appear when I attempt to write to file?
在这个程序中,我试图编写一个文件来显示用户输入的未知数量的记录。每条记录都有以下字段:名字、姓氏、地址、城市、州、邮政编码和 Phone 号码。我假设最好的方法是用上面的字段定义一个结构 Record,然后声明一个 Records 数组,其中包含与用户输入的记录一样多的记录。为了实现这一点,我将使用一个循环来获取每条记录的每个字段的输入,然后如果用户想继续在 Record 数组中动态分配一个额外的 space 并继续直到用户输入 no。程序编译并创建了文件,但是写的字符很奇怪。是什么原因导致这种情况发生?
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
struct Record
{
char fname[51];
char lname[51];
char address[51];
char city[51];
char state[51];
int zipcode;
int phoneNumber;
};
int main()
{
FILE *fileWriter;
const char filename[] = "data.txt";
char answer = 'y';
int size = 1;
int i = 0;
struct Record *records = NULL;
struct Record *records_temp;
while(answer == 'y' || answer == 'Y')
{
struct Record *records_temp = realloc(records,(size)*sizeof(*records));
if(records_temp == NULL)
{
free(records);
}
records = records_temp;
printf("First Name: \n");
scanf("%s", records[i].fname);
printf("Last Name: \n");
scanf("%s", records[i].lname);
printf("Address: \n");
scanf(" %[^\n]", records[i].address);
printf("City: \n");
scanf("%s", records[i].city);
printf("State: \n");
scanf("%s", records[i].state);
printf("Zipcode: \n");
scanf("%d", &records[i].zipcode);
printf("Phone Number: \n");
scanf("%d", &records[i].phoneNumber);
//stores all record info
printf("Are there anymore records? [y/n] ");
answer = getchar();
if(answer == 'y' || answer == 'Y')
{
size++;
records[i++];
printf("\n");
}
//open file
fileWriter = fopen(filename,"wb");
if(fileWriter != NULL)
{
if(fwrite(records,sizeof(*records),size,fileWriter) != 1)
{
fprintf(stderr, "Failed to write to %s\n", filename);
exit(1);
}
fclose(fileWriter);
}
else
{
printf("Error opening file.");
}
}
}
编辑后的版本
我修改了代码并修复了许多发生的错误,但现在我在 scanf( "%c", answer)
处遇到访问冲突
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
struct Record
{
char fname[51];
char lname[51];
char address[51];
char city[51];
char state[51];
char zipcode[51];
char phoneNumber[51];
};
int main()
{
FILE *fileWriter;
const char filename[] = "data.txt";
char answer = 'y';
char a = 'n';
int size = 1;
int i = 0;
struct Record *records;
struct Record *records_temp = NULL;
while(answer == 'y' || answer == 'Y')
{
struct Record *records_temp = calloc((size),sizeof(*records));
records = records_temp;
printf("First Name: \n");
scanf("%s", records[size-1].fname);
printf("Last Name: \n");
scanf("%s", records[size-1].lname);
printf("Address: \n");
scanf(" %[^\n]", records[size-1].address);
printf("City: \n");
scanf("%s", records[size-1].city);
printf("State: \n");
scanf("%s", records[size-1].state);
printf("Zipcode: \n");
scanf("%s", records[size-1].zipcode);
printf("Phone Number: \n");
scanf("%s", records[size-1].phoneNumber);
//stores all record info
printf("Are there anymore records? [y/n] ");
scanf(" %c", answer);
if(answer == 'y' || answer == 'Y')
{
size++;
printf("\n");
}
}
//open file
fileWriter = fopen(filename,"wb");
if(fileWriter != NULL)
{
for(;i< size; i++)
{
fprintf(fileWriter,"%s\n",records[i].fname);
fprintf(fileWriter,"%s\n",records[i].lname);
fprintf(fileWriter,"%s\n",records[i].address);
fprintf(fileWriter,"%s\n",records[i].city);
fprintf(fileWriter,"%s\n",records[i].state);
fprintf(fileWriter,"%d\n",records[i].zipcode);
fprintf(fileWriter,"%d\n",records[i].phoneNumber);
}
fclose(fileWriter);
}
else
{
printf("Error opening file.");
}
}
如果你分配内存,这块内存不会被清除。
char *data = (char*)malloc(100);
这确实为 100 个字符分配了内存。但是内存可以包含随机数据。如果您从此地址写入,您最终可能会将随机数据写入文件。
清除内存以确保没有随机数据。
memset(data, 0, 100);
或 struct
:
struct Demo {
int a;
int b;
};
Demo *demo = (Demo*)malloc(sizeof(Demo));
memset(demo, 0, sizeof(Demo));
您的代码已更正
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct Record
{
char fname[51];
char lname[51];
char address[51];
char city[51];
char state[51];
int zipcode;
int phoneNumber;
};
int main()
{
char answer = 'y';
int size = 0;
Record *records = NULL;
do {
++size;
// resize records array.
if (records == NULL) {
records = (Record*)malloc(sizeof(Record)*size);
} else {
records = (Record*)realloc(records, sizeof(Record)*size);
}
// Get a pointer to the current record.
Record *currentRecord = &records[size-1];
// Clear the record
memset(currentRecord, 0, sizeof(Record));
// Ask for all data.
printf("First Name: \n");
scanf("%s", currentRecord->fname);
printf("Last Name: \n");
scanf("%s", currentRecord->lname);
printf("Address: \n");
scanf(" %[^\n]", currentRecord->address);
printf("City: \n");
scanf("%s", currentRecord->city);
printf("State: \n");
scanf("%s", currentRecord->state);
printf("Zipcode: \n");
scanf("%d", &(currentRecord->zipcode));
printf("Phone Number: \n");
scanf("%d", &(currentRecord->phoneNumber));
// Ask for more.
printf("Are there anymore records? [y/n] ");
answer = getchar();
printf("\n");
} while (answer == 'y'||answer == 'Y');
// Write all records
const char filename[] = "data.txt";
FILE *fileWriter = fopen(filename, "wb");
if (fileWriter != NULL) {
if (fwrite(records, sizeof(Record), size, fileWriter) != size) {
fprintf(stderr, "Failed to write to %s\n", filename);
exit(1);
}
fclose(fileWriter);
} else {
printf("Error opening file.");
}
}
fwrite(records,sizeof(*records),size,fileWriter)
有几个问题:
struct Record
包含 5 个以 null 结尾的字符串,因此您的文件将包含 5 个空字符分隔这些字符串,您可能需要换行符。
struct Record
包含 2 个整数,它们作为二进制数据写入文件,并且肯定符合 "strange characters appearing in the file".
您可以通过根据其特定类型编写这些字段中的每一个来修复它:
fprintf(fileWriter,"%s\n",records->fname);
fprintf(fileWriter,"%s\n",records->lname);
fprintf(fileWriter,"%s\n",records->address);
fprintf(fileWriter,"%s\n",records->city);
fprintf(fileWriter,"%s\n",records->state);
fprintf(fileWriter,"%d\n",records->zipcode);
fprintf(fileWriter,"%d\n",records->phoneNumber);
回答 OP 的评论问题询问为什么程序自动退出,我建议这样做(通过示例)。请注意 %c
之前的 ' '
space,它会清除任何前面的白色 space。
#include<stdio.h>
int main(void) {
int phone;
char answer;
scanf("%d", &phone); // leaves newline in buffer
//answer = getchar(); // reads the newline still in buffer
scanf(" %c", &answer); // skips preceding white-space
return 0;
}
在这个程序中,我试图编写一个文件来显示用户输入的未知数量的记录。每条记录都有以下字段:名字、姓氏、地址、城市、州、邮政编码和 Phone 号码。我假设最好的方法是用上面的字段定义一个结构 Record,然后声明一个 Records 数组,其中包含与用户输入的记录一样多的记录。为了实现这一点,我将使用一个循环来获取每条记录的每个字段的输入,然后如果用户想继续在 Record 数组中动态分配一个额外的 space 并继续直到用户输入 no。程序编译并创建了文件,但是写的字符很奇怪。是什么原因导致这种情况发生?
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
struct Record
{
char fname[51];
char lname[51];
char address[51];
char city[51];
char state[51];
int zipcode;
int phoneNumber;
};
int main()
{
FILE *fileWriter;
const char filename[] = "data.txt";
char answer = 'y';
int size = 1;
int i = 0;
struct Record *records = NULL;
struct Record *records_temp;
while(answer == 'y' || answer == 'Y')
{
struct Record *records_temp = realloc(records,(size)*sizeof(*records));
if(records_temp == NULL)
{
free(records);
}
records = records_temp;
printf("First Name: \n");
scanf("%s", records[i].fname);
printf("Last Name: \n");
scanf("%s", records[i].lname);
printf("Address: \n");
scanf(" %[^\n]", records[i].address);
printf("City: \n");
scanf("%s", records[i].city);
printf("State: \n");
scanf("%s", records[i].state);
printf("Zipcode: \n");
scanf("%d", &records[i].zipcode);
printf("Phone Number: \n");
scanf("%d", &records[i].phoneNumber);
//stores all record info
printf("Are there anymore records? [y/n] ");
answer = getchar();
if(answer == 'y' || answer == 'Y')
{
size++;
records[i++];
printf("\n");
}
//open file
fileWriter = fopen(filename,"wb");
if(fileWriter != NULL)
{
if(fwrite(records,sizeof(*records),size,fileWriter) != 1)
{
fprintf(stderr, "Failed to write to %s\n", filename);
exit(1);
}
fclose(fileWriter);
}
else
{
printf("Error opening file.");
}
}
}
编辑后的版本 我修改了代码并修复了许多发生的错误,但现在我在 scanf( "%c", answer)
处遇到访问冲突#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
struct Record
{
char fname[51];
char lname[51];
char address[51];
char city[51];
char state[51];
char zipcode[51];
char phoneNumber[51];
};
int main()
{
FILE *fileWriter;
const char filename[] = "data.txt";
char answer = 'y';
char a = 'n';
int size = 1;
int i = 0;
struct Record *records;
struct Record *records_temp = NULL;
while(answer == 'y' || answer == 'Y')
{
struct Record *records_temp = calloc((size),sizeof(*records));
records = records_temp;
printf("First Name: \n");
scanf("%s", records[size-1].fname);
printf("Last Name: \n");
scanf("%s", records[size-1].lname);
printf("Address: \n");
scanf(" %[^\n]", records[size-1].address);
printf("City: \n");
scanf("%s", records[size-1].city);
printf("State: \n");
scanf("%s", records[size-1].state);
printf("Zipcode: \n");
scanf("%s", records[size-1].zipcode);
printf("Phone Number: \n");
scanf("%s", records[size-1].phoneNumber);
//stores all record info
printf("Are there anymore records? [y/n] ");
scanf(" %c", answer);
if(answer == 'y' || answer == 'Y')
{
size++;
printf("\n");
}
}
//open file
fileWriter = fopen(filename,"wb");
if(fileWriter != NULL)
{
for(;i< size; i++)
{
fprintf(fileWriter,"%s\n",records[i].fname);
fprintf(fileWriter,"%s\n",records[i].lname);
fprintf(fileWriter,"%s\n",records[i].address);
fprintf(fileWriter,"%s\n",records[i].city);
fprintf(fileWriter,"%s\n",records[i].state);
fprintf(fileWriter,"%d\n",records[i].zipcode);
fprintf(fileWriter,"%d\n",records[i].phoneNumber);
}
fclose(fileWriter);
}
else
{
printf("Error opening file.");
}
}
如果你分配内存,这块内存不会被清除。
char *data = (char*)malloc(100);
这确实为 100 个字符分配了内存。但是内存可以包含随机数据。如果您从此地址写入,您最终可能会将随机数据写入文件。
清除内存以确保没有随机数据。
memset(data, 0, 100);
或 struct
:
struct Demo {
int a;
int b;
};
Demo *demo = (Demo*)malloc(sizeof(Demo));
memset(demo, 0, sizeof(Demo));
您的代码已更正
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct Record
{
char fname[51];
char lname[51];
char address[51];
char city[51];
char state[51];
int zipcode;
int phoneNumber;
};
int main()
{
char answer = 'y';
int size = 0;
Record *records = NULL;
do {
++size;
// resize records array.
if (records == NULL) {
records = (Record*)malloc(sizeof(Record)*size);
} else {
records = (Record*)realloc(records, sizeof(Record)*size);
}
// Get a pointer to the current record.
Record *currentRecord = &records[size-1];
// Clear the record
memset(currentRecord, 0, sizeof(Record));
// Ask for all data.
printf("First Name: \n");
scanf("%s", currentRecord->fname);
printf("Last Name: \n");
scanf("%s", currentRecord->lname);
printf("Address: \n");
scanf(" %[^\n]", currentRecord->address);
printf("City: \n");
scanf("%s", currentRecord->city);
printf("State: \n");
scanf("%s", currentRecord->state);
printf("Zipcode: \n");
scanf("%d", &(currentRecord->zipcode));
printf("Phone Number: \n");
scanf("%d", &(currentRecord->phoneNumber));
// Ask for more.
printf("Are there anymore records? [y/n] ");
answer = getchar();
printf("\n");
} while (answer == 'y'||answer == 'Y');
// Write all records
const char filename[] = "data.txt";
FILE *fileWriter = fopen(filename, "wb");
if (fileWriter != NULL) {
if (fwrite(records, sizeof(Record), size, fileWriter) != size) {
fprintf(stderr, "Failed to write to %s\n", filename);
exit(1);
}
fclose(fileWriter);
} else {
printf("Error opening file.");
}
}
fwrite(records,sizeof(*records),size,fileWriter)
有几个问题:
struct Record
包含 5 个以 null 结尾的字符串,因此您的文件将包含 5 个空字符分隔这些字符串,您可能需要换行符。struct Record
包含 2 个整数,它们作为二进制数据写入文件,并且肯定符合 "strange characters appearing in the file".
您可以通过根据其特定类型编写这些字段中的每一个来修复它:
fprintf(fileWriter,"%s\n",records->fname);
fprintf(fileWriter,"%s\n",records->lname);
fprintf(fileWriter,"%s\n",records->address);
fprintf(fileWriter,"%s\n",records->city);
fprintf(fileWriter,"%s\n",records->state);
fprintf(fileWriter,"%d\n",records->zipcode);
fprintf(fileWriter,"%d\n",records->phoneNumber);
回答 OP 的评论问题询问为什么程序自动退出,我建议这样做(通过示例)。请注意 %c
之前的 ' '
space,它会清除任何前面的白色 space。
#include<stdio.h>
int main(void) {
int phone;
char answer;
scanf("%d", &phone); // leaves newline in buffer
//answer = getchar(); // reads the newline still in buffer
scanf(" %c", &answer); // skips preceding white-space
return 0;
}