如何获得在线会员数量?
How to get a number of online members?
我有一个命令可以计算成员和机器人并分别输出它们。然后我想输出在线用户数。这可能吗?
此命令获取成员和机器人计数
if message.content.startswith('<count'):
membersInServer = message.guild.members
channel = message.channel
# Filter to the list, returns a list of bot-members
botsInServer = list(filter(filterOnlyBots, membersInServer))
botsInServerCount = len(botsInServer)
# (Total Member count - bot count) = Total user count
usersInServerCount = message.guild.member_count - botsInServerCount
msg = discord.Embed(title="Amount of Human Members in this Discord:", description=usersInServerCount, color=0x00FD00)
msg.add_field(name="Amount of Bot Users in this Discord:",value=botsInServerCount, inline=False)
await channel.send(embed=msg)
def filterOnlyBots(member):
return member.bot
我试过 client.member.status 并且 returns 在线
每个Member has a status property, which you can use it to check if the status is offline与否。
然后,您可以按离线状态过滤 membersInServer
。
onlineMembersInServer = list(filter(filterOnlyOnlineMembers, membersInServer))
onlineMembersCount = len(onlineMembersInServer)
# Somewhere...
def filterOnlyOnlineMembers(member):
return member.status != 'offline'
请注意,它计算在线用户和机器人
如果您只想过滤在线用户,您可以将过滤器更改为:
# Set the filter to be a non-offline member, and the member not being a bot.
def filterOnlyOnlineMembers(member):
return member.status != 'offline' and not member.bot
请注意,如果服务器很大,这可能会出现性能问题。
编辑
正如@Patrick Haugh 所提到的,您可以将其制作成 1-liner
sum(member.status!=discord.Status.offline and not member.bot for member in message.guild.members)
我有一个命令可以计算成员和机器人并分别输出它们。然后我想输出在线用户数。这可能吗?
此命令获取成员和机器人计数
if message.content.startswith('<count'):
membersInServer = message.guild.members
channel = message.channel
# Filter to the list, returns a list of bot-members
botsInServer = list(filter(filterOnlyBots, membersInServer))
botsInServerCount = len(botsInServer)
# (Total Member count - bot count) = Total user count
usersInServerCount = message.guild.member_count - botsInServerCount
msg = discord.Embed(title="Amount of Human Members in this Discord:", description=usersInServerCount, color=0x00FD00)
msg.add_field(name="Amount of Bot Users in this Discord:",value=botsInServerCount, inline=False)
await channel.send(embed=msg)
def filterOnlyBots(member):
return member.bot
我试过 client.member.status 并且 returns 在线
每个Member has a status property, which you can use it to check if the status is offline与否。
然后,您可以按离线状态过滤 membersInServer
。
onlineMembersInServer = list(filter(filterOnlyOnlineMembers, membersInServer))
onlineMembersCount = len(onlineMembersInServer)
# Somewhere...
def filterOnlyOnlineMembers(member):
return member.status != 'offline'
请注意,它计算在线用户和机器人
如果您只想过滤在线用户,您可以将过滤器更改为:
# Set the filter to be a non-offline member, and the member not being a bot.
def filterOnlyOnlineMembers(member):
return member.status != 'offline' and not member.bot
请注意,如果服务器很大,这可能会出现性能问题。
编辑
正如@Patrick Haugh 所提到的,您可以将其制作成 1-liner
sum(member.status!=discord.Status.offline and not member.bot for member in message.guild.members)