如何根据端口号对IP地址进行排序？

Question

我正在创建自己的报告工具，我正在尝试弄清楚如何使用端口号对 IP 地址进行排序。

如何使用端口号对 IP 地址进行排序，以便首先对 IP 地址进行排序，然后再通过端口号进行排序。我能够很好地对 IP 地址进行排序，但是当结合端口号时，就变得困难了。

a = ['192.168.0.3 (443/tcp)|', '192.168.0.176 (443/tcp)|', '192.168.0.40 (443/tcp)|', '192.168.0.15 (8443/tcp)|', '192.168.0.16 (8443/tcp)|', '192.168.0.12 (443/tcp)|', '192.168.0.9 (3389/tcp)|', '192.168.0.15 (443/tcp)|', '192.168.0.16 (443/tcp)|', '192.168.0.3 (3389/tcp)|', '192.168.0.14 (443/tcp)|']

print(a.sort(key=lambda s: map(int, s.split('.')))) #this works fine with just IP address not with the current format of (xxx/tcp). The pipe is for delimiters so please ignore.

我想先按 IP 地址排序输出，然后对每个 IP 按端口号排序。因此，例如，前几个结果将是：

a= ['192.168.0.3 (443/tcp)|', '192.168.0.3 (3389/tcp)|', 192.168.0.9 (3389/tcp)|, ...']

Answer 1

使用 re.findall:

import re

def get_ip_port(x):
    *ips, port = map(int, re.findall('\d+', x))
    return ips, port

sorted(a, key=get_ip_port)

输出：

['192.168.0.3 (443/tcp)|',
 '192.168.0.3 (3389/tcp)|',
 '192.168.0.9 (3389/tcp)|',
 '192.168.0.12 (443/tcp)|',
 '192.168.0.14 (443/tcp)|',
 '192.168.0.15 (443/tcp)|',
 '192.168.0.15 (8443/tcp)|',
 '192.168.0.16 (443/tcp)|',
 '192.168.0.16 (8443/tcp)|',
 '192.168.0.40 (443/tcp)|',
 '192.168.0.176 (443/tcp)|']

解释：

map(int, re.findall('\d+', x)): 求出所有数字并使它们成为int
*ips, port：解压上述 ints 并重新打包成除了最后一个 (*ips) 和最后一个 (port)
sorted(a, key=get_ip_port)：作为get_ip_portreturns两个键（ips，port），sorted排序a首先 ips，然后 port，随心所欲。

Answer 2

您可以使用多个条件进行排序（map(int,e[0].split('.'))作为条件 1，int(e[1].lstrip('(').split('/')[0]) 作为条件 2），如下所示，

>>> a
['192.168.0.3 (443/tcp)|',
 '192.168.0.176 (443/tcp)|',
 '192.168.0.40 (443/tcp)|',
 '192.168.0.15 (8443/tcp)|',
 '192.168.0.16 (8443/tcp)|',
 '192.168.0.12 (443/tcp)|',
 '192.168.0.9 (3389/tcp)|',
 '192.168.0.15 (443/tcp)|',
 '192.168.0.16 (443/tcp)|',
 '192.168.0.3 (3389/tcp)|',
 '192.168.0.14 (443/tcp)|']
>>> [i.split() for i in a]
[['192.168.0.3', '(443/tcp)|'],
 ['192.168.0.176', '(443/tcp)|'],
 ['192.168.0.40', '(443/tcp)|'],
 ['192.168.0.15', '(8443/tcp)|'],
 ['192.168.0.16', '(8443/tcp)|'],
 ['192.168.0.12', '(443/tcp)|'],
 ['192.168.0.9', '(3389/tcp)|'],
 ['192.168.0.15', '(443/tcp)|'],
 ['192.168.0.16', '(443/tcp)|'],
 ['192.168.0.3', '(3389/tcp)|'],
 ['192.168.0.14', '(443/tcp)|']]

>>> sorted([i.split() for i in a],key=lambda e: (map(int,e[0].split('.')),int(e[1].strip('(').split('/')[0])))
[['192.168.0.3', '(443/tcp)|'],
 ['192.168.0.3', '(3389/tcp)|'],
 ['192.168.0.9', '(3389/tcp)|'],
 ['192.168.0.12', '(443/tcp)|'],
 ['192.168.0.14', '(443/tcp)|'],
 ['192.168.0.15', '(443/tcp)|'],
 ['192.168.0.15', '(8443/tcp)|'],
 ['192.168.0.16', '(443/tcp)|'],
 ['192.168.0.16', '(8443/tcp)|'],
 ['192.168.0.40', '(443/tcp)|'],
 ['192.168.0.176', '(443/tcp)|']]

Answer 3

您可以使用 sorted 在一行中完成，如下所示：

sorted(a, key=lambda x:x.split(' ')[0])

如何根据端口号对IP地址进行排序？

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