在 python plotly 包中处理散点图中的图例

Question

我想在 python 中使用 plotly 绘制一个具有特定标记颜色的散点图。但是当我成功做到这一点时，传说并不对应。现在所有标签在图例中都具有相同的颜色（蓝色）。我希望图例用代码中提到的相同颜色代表我数据中的风险。像这样：

蓝色标记=中等偏低
绿色标记=中等
橙色标记=中等偏高

import plotly.express as px
import plotly.graph_objects as go

colorsIdx = {'Moderately Low': 'blue', 'Moderate': 'green', 'Moderately High': 'orange'}
cols = data['Risk'].map(colorsIdx)

fig = px.scatter(data, x="1_Yr_Return", y="Expense_Ratio", color='Risk')

fig.update_traces(marker=dict(size=12, color=cols), selector=dict(mode='markers'))
fig.show()

Answer 1

px.scatter()其实已经知道怎么做了:

import plotly.express as px

colorsIdx = {'Moderately Low': 'blue', 'Moderate': 'green', 'Moderately High': 'orange'}

fig = px.scatter(data, x="1_Yr_Return", y="Expense_Ratio", 
                 color='Risk', color_discrete_map=colorsIdx)

fig.show()

在 python plotly 包中处理散点图中的图例

Manipulating legend in Scatter plot in python plotly package

python

scatter-plot

plotly

jupyter-notebook