生成 Uuid 作为主键

Question

拜托，我在生成 uuid 作为我的用户模型中的主键时遇到了问题。我总是 PHP 错误：Class 'App/Traits/boot' not found in C:/xampp/htdocs/twingle/app/Traits/UsesUuid.php on line 11. 尝试了各种方法但这个错误仍然存在

用户模型(App\User)


<?php

namespace App;

use Illuminate\Notifications\Notifiable;
use Illuminate\Contracts\Auth\MustVerifyEmail;
use Illuminate\Foundation\Auth\User as Authenticatable;
use App\Traits\UsesUuid;

class User extends Authenticatable
{
    use Notifiable,UsesUuid;

    protected $keyType = 'string';

    public $incrementing = false;

    /**
     * The attributes that are mass assignable.
     *
     * @var array
     */
    protected $fillable = [
        'name', 'email', 'password',
    ];

    /**
     * The attributes that should be hidden for arrays.
     *
     * @var array
     */
    protected $hidden = [
        'password', 'remember_token',
    ];

    /**
     * The attributes that should be cast to native types.
     *
     * @var array
     */
    protected $casts = [
        'email_verified_at' => 'datetime',
    ];
}

使用一个特征

UseUuid(App\Traits)

<?php

namespace App\Traits;
use Ramsey\Uuid\Uuid;


trait UsesUuid
{
  public static function UsesUuid()
    {
        boot::creating(function ($model) {
            $model->setAttribute($model->getKeyName(), Uuid::uuid4());
        });
    }
}

用户迁移

    public function up()
    {
        Schema::create('users', function (Blueprint $table) {
            $table->uuid('id')->primary();
            $table->string('name');
            $table->string('email')->unique();
            $table->timestamp('email_verified_at')->nullable();
            $table->string('password');
            $table->rememberToken();
            $table->timestamps();
        });

如有任何帮助，我们将不胜感激。谢谢

Answer 1

你的特质代码看起来很不一致。它应该看起来像这样：

namespace App\Traits;
use Ramsey\Uuid\Uuid;


trait UsesUuid
{
    protected static function boot()
    {
        parent::boot();

        static::creating(function ($model) {
            $model->setAttribute($model->getKeyName(), Uuid::uuid4());
        });
    }
}

这样当在模型中使用特征时，它会自动挂接到该模型的 creating 事件，并确保主键生成为 UUID.

Answer 2

寻找模范观察员。它更干净，而且非常合身。 https://laravel.com/docs/5.8/eloquent#observers

生成 Uuid 作为主键

Generating Uuid as Primary Key

php

uuid

laravel