SQL 用于日期过滤的 WITH 语句

Question

我有几年的价格数据，我需要从中提取特定日期的数据：一年前、一个季度前、一个月前、两周前。我使用 Apache Impala SQL

我尝试使用 WITH 语句创建过滤天数的子集。由于一年前的日期可能是周末或假期，我从 (-370.. -365 天前)

的范围内选择最大日期

WITH yearpast AS (
    SELECT max(quote_date_time) as yearago
    FROM quotes_raw
    WHERE quote_date_time >= adddate(now(), -370) and quote_date_time <= adddate(now(), -365)),

monthpast AS (
    SELECT max(quote_date_time) as monthago
    FROM quotes_raw
    WHERE quote_date_time >= adddate(now(), -33) and quote_date_time <= adddate(now(), -30)
    )

SELECT close_px FROM quotes_raw
    WHERE quote_date_time IN (yearpast.yeargo, monthpast.monthago)

我希望 SELECT 语句使用 yearpast 的 quote_date_time 作为过滤器，但我收到了一个错误。

Answer 1

你需要参考cte:

WITH yearpast AS (
    SELECT max(quote_date_time)
    FROM quotes_raw
    WHERE quote_date_time >= adddate(now(), -370) and quote_date_time <= adddate(now(), -365)
)
SELECT close_px 
FROM quotes_raw
WHERE quote_date_time IN (SELECT yearpast.quote_date_time FROM yearpast);

编辑：

WITH yearpast AS (
    SELECT max(quote_date_time) as yearago
    FROM quotes_raw
    WHERE quote_date_time>=adddate(now(),-370) and quote_date_time <= adddate(now(), -365)),

monthpast AS (
    SELECT max(quote_date_time) as monthago
    FROM quotes_raw
    WHERE quote_date_time >= adddate(now(), -33) and quote_date_time <= adddate(now(), -30)
    )

SELECT close_px 
FROM quotes_raw
WHERE quote_date_time IN (SELECT yearpast.yeargo FROM yearpast
                          UNION ALL SELECT monthpast.monthago FROM monthpast)

Answer 2

仅使用 order by 和 limit 怎么样？

select qr.*from quotes_raw qr
where quote_date_time >= adddate(now(), -370)
order by quote_date_time
limit 1;

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