如何获得每个年龄段的总数？

Question

proc sql;
 create table final as select drink,
 count(distinct id) as total_persons,
 count(distinct case when age_cat = '20-25' then id end) as tot_20_25, 
 count(distinct case when age_cat = '25-30' then id end) astot_25_30, 
 count(distinct case when age_cat = '30-35' then id end) as tot_30_35 
 from old_table
 group by drink
 order by total_persons
 quit;

这个 table 给了我我想要的，但我想要多一行作为所有人的总数，如果从上面删除，每个 category.I 可以获得正确数字的单行通过声明对组进行编码。有什么方法可以同时处理两种情况，按饮料，并且每个类别的总计 table 相同？

Answer 1

您可以使用 union all:

proc sql;
 create table final as
     select drink,
            count(distinct id) as total_persons,
            count(distinct case when age_cat = '20-25' then id end) as tot_20_25, 
            count(distinct case when age_cat = '25-30' then id end) as tot_25_30, 
            count(distinct case when age_cat = '30-35' then id end) as tot_30_35 
     from old_table
     group by drink
     union all
     select 'Total',
            count(distinct id) as total_persons,
            count(distinct case when age_cat = '20-25' then id end) as tot_20_25, 
            count(distinct case when age_cat = '25-30' then id end) as tot_25_30, 
            count(distinct case when age_cat = '30-35' then id end) as tot_30_35 
     from old_table;

如何获得每个年龄段的总数？

How to get totals for each age category?

sql

proc-sql