单击按钮为 DataGridView 添加多个附件

Adding Multiple attachments for a DataGridView with Button Click

我编写了这段代码,用于通过单击按钮向 datagridview 添加多个附件,但我一次只能添加一个附件。单击下一个按钮不会添加多个附件,请提供解决方案,

谢谢

这是我试过的代码

       OpenFileDialog ofdialog = new OpenFileDialog();
        ofdialog.Multiselect = true;

        DataTable dt = new DataTable();
        dt.Columns.Add("Attachments");

        var res = ofdialog.ShowDialog();


           string[] filename = ofdialog.FileNames;
           string[] sfilename =  ofdialog.SafeFileNames;

           foreach (string fn in filename)
           {
               dt.Rows.Add(fn);
           }


            dataGridView1.DataSource = dt.DefaultView;
            dataGridView1.Columns["Attachments"].Width = 500;

最后一行的断点(来自评论):嗯,当然这不能解决问题,但现在您知道 DataTable 本身是错误的。现在 向上 您的带有断点的代码。您可以在 DataTable dt = new DataTable(); 行上设置它并查看上面的行,当悬停在 ofdialog 上方时,查看它在 FileNames.

中的文件集合

使用 OpenFileDialog1.Multiselect = True 时,您得到的文件数应该等于您在 OpenFileDialog 中选择的文件数。

下一个候选是 filename 数组,断点在 foreach 上,检查此数组中的项目数。

这是我用来比较的代码:

C#(已转换):

OpenFileDialogDXF.Title = "Choose your files";
OpenFileDialogDXF.InitialDirectory = @"C:\users\XXXXX\Documents\";
OpenFileDialogDXF.Filter = "DXF Files|*.dxf";
OpenFileDialogDXF.Multiselect = true;

if (OpenFileDialogDXF.ShowDialog() == DialogResult.OK)
{
    for (var ir = 0; ir <= OpenFileDialogDXF.FileNames.Count - 1; ir++)
        LoadDXF(OpenFileDialogDXF.FileNames(ir));
}

VB.NET:

Private Sub BtnOpenDxf_Click(sender As Object, e As EventArgs) Handles BtnOpenDxf.Click
    OpenFileDialogDXF.Title = "Choose your files"
    OpenFileDialogDXF.InitialDirectory = "C:\users\XXXXX\Documents\"
    OpenFileDialogDXF.Filter = "DXF Files|*.dxf"
    OpenFileDialogDXF.Multiselect = True

    If OpenFileDialogDXF.ShowDialog() = DialogResult.OK Then
        For ir = 0 To OpenFileDialogDXF.FileNames.Count - 1
            Call LoadDXF(OpenFileDialogDXF.FileNames(ir))
        Next
    End If

其中 LoadDXF 是我处理每个文件的自定义子程序。

编辑:

想想你的代码,如果 OpenFileDialog 得到多个结果,我会在这一行寻找问题:

string[] filename = ofdialog.FileNames;

可能需要一些转换,例如 .ToArray()