如何从推送通知点击打开图像？

Question

在我的应用程序中，我可以选择捕获屏幕截图并将其保存在自定义目录中（例如 /storage/emulated/0/MyApp/screenshots/image.jpeg）。

所以，我想应用 Pending Intent 用户可以点击通知，屏幕截图将在某些默认查看器上打开...

问题是：如何配置待定意图，以便在用户单击通知图像后在某些默认查看器中打开？

例如：我有一个 Pixel phone 并且有制作屏幕截图的选项，在屏幕截图准备好后我可以点击并打开图像...

Answer 1

 Intent intent = new Intent();
    intent.setAction(android.content.Intent.ACTION_VIEW);
    File file = new File("YOUR_IMAGE"); // set your image path 
    intent.setDataAndType(Uri.fromFile(file), "image/*");

    PendingIntent pIntent = PendingIntent.getActivity(this, 0, intent, 0);

    Notification noti = new NotificationCompat.Builder(this)
            .setContentTitle("Screenshot")
            .setContentText("Image Name")
            .setSmallIcon(R.drawable.ic_launcher)
            .setContentIntent(pIntent).build();

    noti.flags |= Notification.FLAG_AUTO_CANCEL;

    NotificationManager notificationManager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
    notificationManager.notify(0, noti);

Answer 2

终于找到了这篇文章

https://medium.com/@ali.muzaffar/what-is-android-os-fileuriexposedexception-and-what-you-can-do-about-it-70b9eb17c6d0

这是我得到的

清单

<manifest ...>
<application ...>
    <provider
        android:name="android.support.v4.content.FileProvider"
        android:authorities="${applicationId}.provider"
        android:exported="false"
        android:grantUriPermissions="true">
        <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/provider_paths"/>
    </provider>
</application>
</manifest>

创建XML 文件res/xml/provider_paths.xml

<?xml version="1.0" encoding="utf-8"?>
<paths xmlns:android="http://schemas.android.com/apk/res/android">
<external-path name="external_files" path="."/>
</paths>

代码更改

Intent intent = new Intent();
    intent.setAction(android.content.Intent.ACTION_VIEW);

    File file = new File(iImagePath); // set your image path

    Uri uri = FileProvider.getUriForFile(iC, iC.getApplicationContext().getPackageName() + ".provider", file);
    intent.setDataAndType(uri, "image/*");
    intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);

    PendingIntent pIntent = PendingIntent.getActivity(iC, 0, intent, 0);

    Bitmap bm = BitmapFactory.decodeFile(iImagePath);

    NotificationCompat.Builder builder = mScreenshotBuilder.setContentTitle(iC.getString(R.string.screenshot_saved))//
                                                           .setContentText(iC.getString(R.string.tap_to_view_your_screenshot))//
                                                           .setContentIntent(pIntent);

如何从推送通知点击打开图像？

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