如何在 oracle 中拆分由 space 分隔的字符串并将每个单词添加到 Oracle 11g 中的不同行？

Question

我正在尝试拆分字符串并将每个单词添加到单独的行中。

with data as (
  select 100 as id, 'python java' as src from dual
)
 select id, level as lvl,
        regexp_substr( src || '" "' , '([[:space:]0-9/:])', 1, level, null, 1 ) as token
   from data
connect by level <= regexp_count( src || '" "' , '([[:space:]0-9/:])' )
       and prior id = id
       and prior sys_guid() is not null
;

我希望 python 和 java 在不同的行中。

Answer 1

您的正则表达式似乎有点混乱。我想你想要更像的东西：

regexp_substr( src , '(.*?)([[:space:]0-9/:]|$)', 1, level, null, 1 )

db<>fiddle

Answer 2

您可以将 regexp_substr() 和 regexp_count() 与 connect by level<... 表达式组合使用：

with t as
(
  select 100 as id, 'python java' as src from dual
)
 select id, level as lvl, regexp_substr(src, '[^[:space:]]+',1,level) as token
   from t 
connect by level<= regexp_count(src,'[[:space:]]')+1
    and prior id = id
    and prior sys_guid() is not null;

Demo

如何在 oracle 中拆分由 space 分隔的字符串并将每个单词添加到 Oracle 11g 中的不同行？

How to split a string seperated by space in oracle and add each word to a different row in Oracle 11g?

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regexp-substr