Python lxml：如何使用 xpath 选择器获取 XML 标签名称？

Question

我正在尝试使用 Python 和 lxml 解析以下 XML：

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="/bind9.xsl"?>
<isc version="1.0">
  <bind>
    <statistics version="2.2">
      <memory>
        <summary>
          <TotalUse>1232952256
          </TotalUse>
          <InUse>835252452
          </InUse>
          <BlockSize>598212608
          </BlockSize>
          <ContextSize>52670016
          </ContextSize>
          <Lost>0
          </Lost>
        </summary>
      </memory>
    </statistics>
  </bind>
</isc>

目标是提取 bind/statistics/memory/summary 下每个元素的标签名称和文本，以生成以下映射：

TotalUse: 1232952256
InUse: 835252452
BlockSize: 598212608
ContextSize: 52670016
Lost: 0

我已经设法提取了元素值，但我无法找出 xpath 表达式来获取元素标签名称。

示例脚本：

from lxml import etree as et

def main():

    xmlfile = "bind982.xml"
    location = "bind/statistics/memory/summary/*"
    label_selector = "??????" ## what to put here...?
    value_selector = "text()"

    with open(xmlfile, "r") as data:
        xmldata = et.parse(data)

        etree = xmldata.getroot()

        statlist = etree.xpath(location)

        for stat in statlist:
            label = stat.xpath(label_selector)[0]
            value = stat.xpath(value_selector)[0]
            print "{0}: {1}".format(label, value)

if __name__ == '__main__':
    main()

我知道我可以使用 value = stat.tag 而不是 stat.xpath()，但脚本必须足够通用才能处理标签选择器不同的 XML 的其他部分。

什么 xpath 选择器 return 元素的标签名称？

Answer 1

我认为这两个值不需要 XPath，元素节点具有 tag 和 text 属性，因此例如使用列表理解：

[(element.tag, element.text) for element in etree.xpath(location)]

或者如果你真的想使用 XPath

result = [(element.xpath('name()'), element.xpath('string()')) for element in etree.xpath(location)]

你当然也可以构造一个字典列表：

result = [{ element.tag : element.text } for element in root.xpath(location)]

或

result = [{ element.xpath('name()') : element.xpath('string()') } for element in etree.xpath(location)]

Answer 2

只需使用 XPath 的 name()，并删除零索引，因为此 returns 是一个字符串而不是列表。

from lxml import etree as et

def main():

    xmlfile = "ExtractXPathTagName.xml"
    location = "bind/statistics/memory/summary/*"
    label_selector = "name()"                         ## what to put here...?
    value_selector = "text()"

    with open(xmlfile, "r") as data:
        xmldata = et.parse(data)

        etree = xmldata.getroot()

        statlist = etree.xpath(location)

        for stat in statlist:
            label = stat.xpath(label_selector)
            value = stat.xpath(value_selector)[0]
            print("{0}: {1}".format(label, value).strip())

if __name__ == '__main__':
    main()

输出

TotalUse: 1232952256    
InUse: 835252452    
BlockSize: 598212608    
ContextSize: 52670016    
Lost: 0

Python lxml：如何使用 xpath 选择器获取 XML 标签名称？

Python lxml: how to fetch XML tag names with xpath selector?

python

xml

xpath

lxml