使用 Newtonsoft 在 C# 中使用 JSON 架构验证 JSON

Question

使用 JSON 架构 return 验证 JSON 始终为真。 Newtonsoft 用于验证并使用模式和数据测试 here。它 return 总是 'No errors found. JSON validates against the schema'.

请找到我的 JSON 架构。


{
  "schema": {
    "definitions": {
    },
    "$schema": "http://json-schema.org/draft-07/schema#",
    "$id": "http://example.com/root.json",
    "type": "object",
    "widget": { "formlyConfig": { "type": "accordion" } },
    "title": "The Root Schema",
    "required": [
      "accordion1",
      "accordion2",
      "accordion3"
    ],
    "properties": {
      "accordion1": {
        "$id": "#/properties/accordion1",
        "type": "object",
        "title": "The Accordion1 Schema",
        "required": [
          "firstname",
          "age"
        ],
        "properties": {
          "firstname": {
            "$id": "#/properties/accordion1/properties/firstname",
            "type": "string",
            "title": "The Firstname Schema",
            "default": "firstname pvr1"
          },
          "age": {
            "$id": "#/properties/accordion1/properties/age",
            "type": "integer",
            "title": "The Age Schema",
            "default": 21
          }
        }
      },
      "accordion2": {
        "$id": "#/properties/accordion2",
        "type": "object",
        "title": "The Accordion2 Schema",
        "required": [
          "firstname",
          "age"
        ],
        "properties": {
          "firstname": {
            "$id": "#/properties/accordion2/properties/firstname",
            "type": "string",
            "title": "The Firstname Schema",
            "default": "firstName2"
          },
          "age": {
            "$id": "#/properties/accordion2/properties/age",
            "type": "integer",
            "title": "The Age Schema",
            "default": 31
          }
        }
      },
      "accordion3": {
        "$id": "#/properties/accordion3",
        "type": "object",
        "title": "The Accordion3 Schema",
        "required": [
          "firstname",
          "age"
        ],
        "properties": {
          "firstname": {
            "$id": "#/properties/accordion3/properties/firstname",
            "type": "string",
            "title": "The Firstname Schema",
            "default": "firstnaem3"
          },
          "age": {
            "$id": "#/properties/accordion3/properties/age",
            "type": "integer",
            "title": "The Age Schema",
            "default": 10
          }
        }
      }
    },
      'additionalProperties': false
  }
}

请查找JSON

{ 
   "accordion1":{ 
      "firstname":"JSON ACCORD PALANIVELRAJAN",
      "age":29
   },
   "accordion2":{ 
      "firstname":"JSON ACCORD LAKSHMANAN",
      "age":39
   },
   "accordion3":{ 
      "firstname":null,
      "age":49
   }
}

我试图将名字更改为整数并删除 accordion1 中的第一个。 return 在所有情况下都是如此。

请指教

请找到使用 JSON 架构验证 JSON 的代码。

模型是一个 JObject，它是一个有效的 JSON。

JsonSchema json_schema = JsonSchema.Parse(schema);
IList<string> messages;
bool valid = model.IsValid(json_schema, out messages);
return valid;

Answer 1

JsonSchema 已弃用，已移至单独的包：Newtonsoft.Json.Schema。使用这个包，我能够根据你的模式验证你的 JSON （我确实删除了外部 schema 元素，因为它实际上是无效的，并导致模式无法正确验证 - 我想你可能'我已经把它放在那里了，因为旧的 JsonSchema class 否则无法解析模式！），如果我将 JSON 更改为无效的形状，删除了必需的元素，或者将数据更改为无效类型：

            string data = File.ReadAllText("data.json");
            string schema = File.ReadAllText("data.schema.json");

            var model = JObject.Parse(data);
            var json_schema = JSchema.Parse(schema);

            IList<string> messages;
            bool valid = model.IsValid(json_schema, out messages); // properly validates

我正在使用 .NET Core 2.2、Newtonsoft.Json 12.0.2 和 Newtonsoft.Json.Schema 3.0.11，以防万一。请注意，Newtonsoft.Json.Schema 包对商业用途有限制 - 检查许可！

使用 Newtonsoft 在 C# 中使用 JSON 架构验证 JSON

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