如何从 txt 文件中的拆分行制作嵌套列表？

Question

我想通过 space 字符“ ”将我的 txt 文件中的每一行分成 3 部分，并将这 3 部分变成每一行的列表，并将所有这些列表变成一个更大的列表

我的 txt 文件：

1998/04/20 17:38:51.604 16.863014
1998/04/20 17:38:52.204 1.947639
1998/04/20 17:38:54.404 27.278648
1998/04/20 17:39:02.605 0.325151
1998/04/20 17:39:04.705 7.002871

我的代码：

dataList = []
metaData = ['', '', '']

with open('data.txt', 'r') as myTxt:
    for line in myTxt:
        metaData[0] = line.split(' ')[0]
        metaData[1] = line.split(' ')[1]
        metaData[2] = line.split(' ')[2]
        dataList.append(metaData)
    print(dataList)

我希望输出是这样的：

[[1998/04/20, 17:38:51.604, 16.863014],
[1998/04/20, 17:38:52.204, 1.947639],
[1998/04/20, 17:38:54.404, 27.278648],
[1998/04/20, 17:39:02.605, 0.325151],
[1998/04/20, 17:39:04.705, 7.002871]]

但我得到的是：

[[1998/04/20, 17:39:04.705, 7.002871],
[1998/04/20, 17:39:04.705, 7.002871],
[1998/04/20, 17:39:04.705, 7.002871],
[1998/04/20, 17:39:04.705, 7.002871],
[1998/04/20, 17:39:04.705, 7.002871]]

有人知道如何解决这个问题吗？谢谢

Answer 1

试试这个：

with open('data.txt', 'r') as myTxt:
    dataList = [i.strip().split() for i in myTxt.readlines()]

输出 :

[['1998/04/20', '17:38:51.604', '16.863014'], 
 ['1998/04/20', '17:38:52.204', '1.947639'], 
 ['1998/04/20', '17:38:54.404', '27.278648'], 
 ['1998/04/20', '17:39:02.605', '0.325151'], 
 ['1998/04/20', '17:39:04.705', '7.002871']]

根据评论部分的要求，要将列表转换为另一种格式，请尝试以下操作：

dataList = [[' '.join([i, j]), k] for i,j,k in dataList]

它应该输出这个：

[['1998/04/20 17:38:51.604', '16.863014'], 
 ['1998/04/20 17:38:52.204', '1.947639'], 
 ['1998/04/20 17:38:54.404', '27.278648'],
 ['1998/04/20 17:39:02.605', '0.325151'],
 ['1998/04/20 17:39:04.705', '7.002871']]

如果你想在一行中得到上面的结果，你可以这样做:

with open('test2.txt', 'r') as myTxt:
    dataList = [[' '.join(i.strip().split()[:-1]),i.strip().split()[-1]] for i in in myTxt.readlines()]

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