Spark Scala:访问数组内部结构中的数据

Spark Scala: Access data inside struct which is inside of an array

架构如下所示

root
|-- orderitemlist: array (nullable = true)
| |-- element: struct (containsNull = true)
| | |-- internal-material-code: string (nullable = true)
| | |-- lot-number: string (nullable = true)
| | |-- packaging-item-code: string (nullable = true)
| | |-- packaging-item-code-type: string (nullable = true)

如何访问 internal-material-codelot-number

的值

我在创建数据框时这样做

df.withColumn("internalmaterialcode", col("orderitemlist")(0).getItem("internal-material-code"))

还有

df.withColumn("internalmaterialcode", col("orderitemlist")(0)("internal-material-code"))

又如下

df.withColumn("orderitemlistarray", explode(col("orderitemlist"))) 
.withColumn("internalmaterialcode", col("orderitemlistarray").getItem("internal-material-code")) 

又如下

df.withColumn("orderitemlistarray", explode(col("orderitemlist"))) 
.withColumn("internalmaterialcode", col("orderitemlistarray.internal-material-code")) 

但它给出 null

我在 Whosebug 问题上看到了类似的模式,但 none 的答案对我很有用。有人可以回答或指引我到正确的地方吗?

explode 之后,select 新创建的列,它将提供来自 struct fields 的所有数据。

Example:

val va="""{
    "orderitemlist": [{
        "internal-material-code": "123",
        "lot-number": "vv",
        "packaging-item-code": "pp",
        "packaging-item-code-type": "ll"
    },{
        "internal-material-code": "234",
        "lot-number": "vv",
        "packaging-item-code": "pp",
        "packaging-item-code-type": "ll"
    }]
}"""

val df=spark.read.json(Seq(va).toDS).toDF

df.withColumn("arr",explode(col("orderitemlist"))).select("arr.*").show()

Result:

+----------------------+----------+-------------------+------------------------+
|internal-material-code|lot-number|packaging-item-code|packaging-item-code-type|
+----------------------+----------+-------------------+------------------------+
|                   123|        vv|                 pp|                      ll|
|                   234|        vv|                 pp|                      ll|
+----------------------+----------+-------------------+------------------------+

现在您将从数组中的结构中获取所有列..!!

我检查了您共享的代码块,它工作正常。请在这里完成我的工作(作为对早期解决方案的扩展):

>>>df.withColumn("ves", $"orderitemlist.lot-number").show
+--------------------+--------+
|       orderitemlist|     ves|
+--------------------+--------+
|[[123, vv, pp, ll...|[vv, vv]|
+--------------------+--------+

>>>df.withColumn("vew", $"orderitemlist".getItem("lot-number")).show
+--------------------+--------+
|       orderitemlist|     vew|
+--------------------+--------+
|[[123, vv, pp, ll...|[vv, vv]|
+--------------------+--------+