如何将两个变量导出到与通过 PowerShell 连接时相同的 CSV 文件中？

Question

我有一个使用 poshwsus 模块的 PowerShell 脚本，如下所示：

$FileOutput = "C:\WSUSReport\WSUSReport.csv"
$ProcessLog = "C:\WSUSReport\QueryLog2.txt"
$WSUSServers = "C:\WSUSReport\Computers.txt"
$WSUSPort = "8530"

import-module poshwsus 

ForEach ($Server in Get-Content $WSUSServers)
{
    & connect-poshwsusserver $Server -port $WSUSPort | out-file $ProcessLog -append
    $r1 = & Get-PoshWSUSClient | select @{name="Computer";expression={$_.FullDomainName}},@{name="LastUpdated";expression={if ([datetime]$_.LastReportedStatusTime -gt [datetime]"1/1/0001 12:00:00 AM") {$_.LastReportedStatusTime} else {$_.LastSyncTime}}}
    $r2 = & Get-PoshWSUSUpdateSummaryPerClient -UpdateScope (new-poshwsusupdatescope) -ComputerScope (new-poshwsuscomputerscope) | Select Computer,NeededCount,DownloadedCount,NotApplicableCount,NotInstalledCount,InstalledCount,FailedCount

}

我需要做的是导出 CSV 输出，包括带有列的结果（如 "inner join"）：

Computer, NeededCount, DownloadedCount, NotApplicableCount, NotINstalledCount, InstalledCount, FailedCount, LastUpdated

我尝试在 foreach 中使用下面的行，但它没有像我预期的那样工作。

$r1 + $r2 | export-csv -NoTypeInformation -append $FileOutput

如果您能提供帮助或建议，我将不胜感激。

编辑 --> 我得到的输出：

ComputerName LastUpdate
X                A
Y                B
X
Y

所以没有错误，$r2 的前两行，$r1 的最后两行，它没有像我预期的那样连接表。

谢谢！

Answer 1

我在这个 post 中找到了我的指导：

像下面这样相应地修改了我的查询，效果很好。

$FileOutput = "C:\WSUSReport\WSUSReport.csv"
$ProcessLog = "C:\WSUSReport\QueryLog.txt"
$WSUSServers = "C:\WSUSReport\Computers.txt"
$WSUSPort = "8530"

import-module poshwsus 

function Join-Records($tab1, $tab2){
    $prop1 = $tab1 | select -First 1 | % {$_.PSObject.Properties.Name} #properties from t1
    $prop2 = $tab2 | select -First 1 | % {$_.PSObject.Properties.Name} #properties from t2
    $join = $prop1 | ? {$prop2 -Contains $_}
    $unique1 = $prop1 | ?{ $join -notcontains $_}
    $unique2 = $prop2 | ?{ $join -notcontains $_}


    if ($join) {
        $tab1 | % {
            $t1 = $_
            $tab2 | % {
                $t2 = $_
                foreach ($prop in $join) {
                    if (!$t1.$prop.Equals($t2.$prop)) { return; }
                }
                $result = @{}                
                $join | % { $result.Add($_,$t1.$_) }
                $unique1 | % { $result.Add($_,$t1.$_) }
                $unique2 | % { $result.Add($_,$t2.$_) }
                [PSCustomObject]$result
            }
        }
    }
}

ForEach ($Server in Get-Content $WSUSServers)
{
    & connect-poshwsusserver $Server -port $WSUSPort | out-file $ProcessLog -append
    $r1 = & Get-PoshWSUSClient | select @{name="Computer";expression={$_.FullDomainName}},@{name="LastUpdated";expression={if ([datetime]$_.LastReportedStatusTime -gt [datetime]"1/1/0001 12:00:00 AM") {$_.LastReportedStatusTime} else {$_.LastSyncTime}}}
    $r2 = & Get-PoshWSUSUpdateSummaryPerClient -UpdateScope (new-poshwsusupdatescope) -ComputerScope (new-poshwsuscomputerscope) | Select Computer,NeededCount,DownloadedCount,NotApplicableCount,NotInstalledCount,InstalledCount,FailedCount
    Join-Records $r1 $r2 | Select Computer,NeededCount,DownloadedCount,NotApplicableCount,NotInstalledCount,InstalledCount,FailedCount, LastUpdated | export-csv -NoTypeInformation -append $FileOutput

}

Answer 2

我认为这可以变得更简单。由于 Select-Object's -Property parameter accepts an array of values, you can create an array of the properties you want to display. The array can be constructed by comparing your two objects' 个属性并输出这些属性的唯一列表。

$selectProperties = $r1.psobject.properties.name | Compare-Object $r2.psobject.properties.name -IncludeEqual -PassThru
$r1,$r2 | Select-Object -Property $selectProperties

Compare-Object 默认情况下将只输出参考对象和差异对象之间的差异。添加 -IncludeEqual 开关显示不同和相等的比较。添加 -PassThru 参数输出比较的实际对象，而不是默认的 PSCustomObject 输出。

如何将两个变量导出到与通过 PowerShell 连接时相同的 CSV 文件中？

How to export two variables into same CSV as joined via PowerShell?

powershell

powershell-5.0

poshwsus