将 JSON 对象映射到 C# class 属性 数组
Map JSON object to C# class property array
JSON
{
"SoftHoldIDs": 444,
"AppliedUsages": [
{
"SoftHoldID": 444,
"UsageYearID": 223232,
"DaysApplied": 0,
"PointsApplied": 1
}
],
"Guests": [
1,
2
]
}
在上面 JSON SoftholdIDs 是整数,AppliedUsages 是 class 数组 属性 in C# Model
问题是——我们如何将 JSON 映射到 class 属性。
Class代码
public class ReservationDraftRequestDto
{
public int SoftHoldIDs { get; set; }
public int[] Guests { get; set; }
public AppliedUsage[] AppliedUsages { get; set; }
}
public class AppliedUsage
{
public int SoftHoldID { get; set; }
public int UsageYearID { get; set; }
public int DaysApplied { get; set; }
public int PointsApplied { get; set; }
}
尝试了以下映射代码
ReservationDraftRequestDto reservationDto = null;
dynamic data = await reservationDraftRequestDto.Content.ReadAsAsync<object>();
reservationDto = JsonConvert.DeserializeObject<ReservationDraftRequestDto>(data.ToString());
你需要改变
dynamic data = await reservationDraftRequestDto.Content.ReadAsAsync<object>();
到
string data = await reservationDraftRequestDto.Content.ReadAsStringAsync();
这会将您的回复读取为字符串
然后做
reservationDto = JsonConvert.DeserializeObject<ReservationDraftRequestDto>(data);
这项工作
using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace ConsoleApp2
{
class Program
{
static void Main(string[] args)
{
string json = @"{""SoftHoldIDs"": 444,""AppliedUsages"": [ {""SoftHoldID"": 444,""UsageYearID"": 223232,""DaysApplied"": 0,""PointsApplied"": 1}],""Guests"": [ 1, 2]}";
Rootobject reservationDto = JsonConvert.DeserializeObject<Rootobject>(json.ToString());
Debug.WriteLine(reservationDto.SoftHoldIDs);
foreach (var guest in reservationDto.Guests)
{
Debug.WriteLine(guest);
}
}
}
public class Rootobject
{
public int SoftHoldIDs { get; set; }
public Appliedusage[] AppliedUsages { get; set; }
public int[] Guests { get; set; }
}
public class Appliedusage
{
public int SoftHoldID { get; set; }
public int UsageYearID { get; set; }
public int DaysApplied { get; set; }
public int PointsApplied { get; set; }
}
}
首先使用 visualstudio 创建 class 将 json 复制为 class。
接下来你在 json 响应中有双引号所以处理它。
Json.NET: Deserilization with Double Quotes
JSON
{
"SoftHoldIDs": 444,
"AppliedUsages": [
{
"SoftHoldID": 444,
"UsageYearID": 223232,
"DaysApplied": 0,
"PointsApplied": 1
}
],
"Guests": [
1,
2
]
} 在上面 JSON SoftholdIDs 是整数,AppliedUsages 是 class 数组 属性 in C# Model
问题是——我们如何将 JSON 映射到 class 属性。 Class代码
public class ReservationDraftRequestDto
{
public int SoftHoldIDs { get; set; }
public int[] Guests { get; set; }
public AppliedUsage[] AppliedUsages { get; set; }
}
public class AppliedUsage
{
public int SoftHoldID { get; set; }
public int UsageYearID { get; set; }
public int DaysApplied { get; set; }
public int PointsApplied { get; set; }
}
尝试了以下映射代码
ReservationDraftRequestDto reservationDto = null;
dynamic data = await reservationDraftRequestDto.Content.ReadAsAsync<object>();
reservationDto = JsonConvert.DeserializeObject<ReservationDraftRequestDto>(data.ToString());
你需要改变
dynamic data = await reservationDraftRequestDto.Content.ReadAsAsync<object>();
到
string data = await reservationDraftRequestDto.Content.ReadAsStringAsync();
这会将您的回复读取为字符串
然后做
reservationDto = JsonConvert.DeserializeObject<ReservationDraftRequestDto>(data);
这项工作
using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace ConsoleApp2
{
class Program
{
static void Main(string[] args)
{
string json = @"{""SoftHoldIDs"": 444,""AppliedUsages"": [ {""SoftHoldID"": 444,""UsageYearID"": 223232,""DaysApplied"": 0,""PointsApplied"": 1}],""Guests"": [ 1, 2]}";
Rootobject reservationDto = JsonConvert.DeserializeObject<Rootobject>(json.ToString());
Debug.WriteLine(reservationDto.SoftHoldIDs);
foreach (var guest in reservationDto.Guests)
{
Debug.WriteLine(guest);
}
}
}
public class Rootobject
{
public int SoftHoldIDs { get; set; }
public Appliedusage[] AppliedUsages { get; set; }
public int[] Guests { get; set; }
}
public class Appliedusage
{
public int SoftHoldID { get; set; }
public int UsageYearID { get; set; }
public int DaysApplied { get; set; }
public int PointsApplied { get; set; }
}
}
首先使用 visualstudio 创建 class 将 json 复制为 class。 接下来你在 json 响应中有双引号所以处理它。 Json.NET: Deserilization with Double Quotes