python 中的密码求解器循环计数

Question

我正在 python 中编写一个程序，允许您输入密码，然后 python 遍历所有 ascii 字符以尝试猜测您的密码。我已经让它工作了，但我试图在其中建立一个运行的计数，看看计算机猜测这个字符的尝试次数。我只是不确定运行thru 计算的迭代次数是否正确？欢迎任何建议。

代码如下.....

password=input("Enter a password:")
print("Your password is: ",password)
print("Your password length is: ",len(password))
length=len(password)
crackedlistx=[]
runthrus=0
lengthx=len(crackedlistx)
passwordlist=password.split()
print("xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx")
while length>len(crackedlistx):
    for i in range(0,length):
        for c in (chr(i) for i in range(0,128)):
            runthrus=runthrus+1
            if password[i]==c:
                crackedlistx.append(c)
                runthrus=runthrus+1
                print("Finding",len(crackedlistx),"of",length,"characters.")
                print("Your password being solved:",crackedlistx)
                print("Percentage complete: ",100*(len(crackedlistx)/length),"%")
print("Your final password solved:",''.join(crackedlistx))
print("Run through's taken:",runthrus)

Answer 1

您不需要第二个 runthrus 增量：

...
runthrus=runthrus+1
if password[i]==c:
    crackedlistx.append(c)
    runthrus=runthrus+1  # delete this line
    print("Finding",len(crackedlistx),"of",length,"characters.")
    ...

此外，您可以将 runthrus=runthrus+1 替换为 runthrus += 1

python 中的密码求解器循环计数

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