为字典的值获取 value_counts()

Question

我非常熟悉如何从 pd.Series return value_counts。但是，我如何从字典的值中获取值计数？

假设我在字典中有以下元组 L:

L = {1: (13600, 14797),
     2: (14700, 14700),
     3: (14700, 10400),
     4: (14600, 17200),
     5: (13600, 14797),
     6: (14600, 17200),
     7: (14700, 10400),
     8: (14700, 10400),
     9: (12800, 14770)}

如何从 L 中得到 value_counts 看起来像：

(14700, 10400) 3
(13600, 14797) 2
(14600, 17200) 2
(14700, 14700) 1
(12800, 14770) 1

这是我目前所拥有的。但是，我认为字典键 1-9 妨碍了我，因为我收到错误 list object is not callable.

list = [(k, v) for k, v in L.items()] 
S = set(L)
F = {}
for i in list(S):
    F[i] = list.count(i)

Answer 1

也许使用 from collections import Counter 是个好主意？

from collections import Counter 
dict(Counter([j for i,j in L.items()]))

Answer 2

使用标准库中的collections.Counter：

Counter(L.values())

Answer 3

你可以试试这个：

L = {1: (13600, 14797),
     2: (14700, 14700),
     3: (14700, 10400),
     4: (14600, 17200),
     5: (13600, 14797),
     6: (14600, 17200),
     7: (14700, 10400),
     8: (14700, 10400),
     9: (12800, 14770)}
vals = [ v for v in L.values()]
counts = []
for i in vals:
    counts.append((i, vals.count(i)))
set(counts)

Answer 4

你提到了pandas.Series.value_counts()，你为什么不试试

pd.Series(L).value_counts()

给出：

(14700, 10400)    3
(14600, 17200)    2
(13600, 14797)    2
(12800, 14770)    1
(14700, 14700)    1
dtype: int64

为字典的值获取 value_counts()

Get value_counts() for values of a dictionary

python

counter

dictionary