在 Bash 中打印一个 table

Question

我在使用 printf 函数或 echo 打印数组中的所有值以打印漂亮的 table 时遇到问题。我试过简单的，但它不是我想要的顺序。


    for i in ${!R[@]}

    do

      printf "%-20s" ${R[i]}

      printf "\n"

    done

what i have what i want

我想要什么

 mteEventComment mteEventActions mteEventEnabled mteEventEntryStatus
                           "80 "            true              active
                           "80 "            true              active
                           "80 "            true              active
                           "80 "            true              active
                           "80 "            true              active
                           "80 "            true              active

我有什么

 mteEventComment mteEventActions mteEventEnabled mteEventEntryStatus
       "80          "        "80          "        "80
         "        "80          "        "80          "
       "80          "       true       true       true
      true       true       true     active     active
    active     active     active     active
script2.sh: line 64: "80: syntax error: operand expected (error token is ""80")



 content of **R array**: First 6 are empty
         "80 " "80 " "80 " "80 " "80 " "80 " true true true true true true active active active active active active

我有 header

printf "$header" "mteEventComment" "mteEventActions" "mteEventEnabled" "mteEventEntryStatus"


mteEventComment mteEventActions mteEventEnabled mteEventEntryStatus

在此之下，我需要我的数组以准确的顺序排列

Answer 1

鉴于 R 中的数据包含带有特殊字符（引号、空格）的值（和潜在的键），您想要引用它们：

for i in "${!R[@]}" 
    do
      printf "%-20s\n" "${R[i]}"
    done

在 Bash 中打印一个 table

Print a table in Bash

bash

printf

echo